can anyone help? its on my quiz & it has a timer :l i only have 23 mins Which table of ordered pairs represents a proportion
2 answers:
You might be interested in
<h2>Steps</h2>
- Standard Form Equation: f(x) = ax² + bx + c
So firstly, since (0,5) is one of our values we can plug it into the standard form equation to solve for the c variable (since 0 will cancel out the a and b variable):
Now we know that the value of c is 5. Next, plug in (-1,12) into the standard form equation and simplify (remember to also plug in 5 for the c variable):
Next, plug (2,15) into the standard form equation and simplify:
Now, with our last two simplified equations we will create a system of equations:
Now, I will be using the elimination method with this system. With the system, add up the equations together and you will get:
From here, we can solve for the a variable. With it, just divide both sides by 3:
Now that we know the value of a, plug it into either equation to solve for the b variable:
Putting all of our obtained values together, your final answer is:
Answer:
51%
Step-by-step explanation:
Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.
<h3>Probability relations</h3>We can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).
The probability of passing one course and failing the other is the sum of the probabilities with a yellow background:
42% +9% = 51%
The probability of passing one or the other is 51%.
__
<em>Additional comment</em>
We can also get there using the relation ...
P(A+B) = P(A) +P(B) -P(AB)
The union of A and B also includes their overlap:
P(A+B) = P(AB') +P(A'B) +P(AB)
In other words, the probability of interest is ...
P(AB') +P(A'B) = P(A) +P(B) -2×P(AB) = 59% +26% -2(17%)
P(AB') +P(A'B) = 51%
