I found an image that corresponds to the above question.
The shape was a rectangle. Its width is 7 units, its length is x.
The shaded area of the rectangle forms a trapezoid.
Area of a trapezoid = [(a+b)/2] * h
63 sq. units = (7+x)/2 * 7
63/7 = (7+x)/2
9 = (7+x)/2
9*2 = 7 + x
18 = 7 + x
18 - 7 = x
11 = x
The value of x is 11 units. It is the length of the rectangle.
Area of the trapezoid = (a+b)/2 * h
63 = (7+11)/2 * 7
63 = 18/2 * 7
63 = 9 * 7
63 = 63
Your answer should be no solution because 7 cant divide into 11
Answer:
B) 1
Step-by-step explanation:
All I did was simplify the equation
1509/1600
(Decimal: 0.943125)
HOPE THIS HELPS!!!! :)
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<span>Let opposite ray be drawn for the base side ray of the given angle.
This gives angle 180° between these two rays.
Angle bisectors of the given angles 50°, 90°, and 150° make respectively half of these angles : 25° , 45° and 75° with the base ray.
Then measure of the angles between the bisectors of the given angles and the drawn opposite ray are 180°-25°=155°, 180°- 45° =135° and 180°- 75° = 105° respectively.</span>
Oh. I thought you meant 3-6, not questions 3 through 6. Sorry :(