It’s D
Let me know if you need an explanation!
Answer:
B) 4
Step-by-step explanation:
We can solve this by observing some pattern.
The powers ending in 4 as unit digit are:
![{8}^{2} , {8}^{6} , {8}^{10} , {8}^{14} , {8}^{20} ,...](https://tex.z-dn.net/?f=%20%7B8%7D%5E%7B2%7D%20%2C%20%7B8%7D%5E%7B6%7D%20%2C%20%7B8%7D%5E%7B10%7D%20%2C%20%7B8%7D%5E%7B14%7D%20%2C%20%7B8%7D%5E%7B20%7D%20%2C...)
The exponents form the sequence:
2,6,10,14,20,...
We need to check if 62 belongs to this sequence.
This is an arithmetic sequence with a common difference of 4 and a first term of 2.
The explicit formula is
![2 + 4(n - 1)](https://tex.z-dn.net/?f=2%20%2B%204%28n%20-%201%29)
We equate this to 62 and solve for n.
![2 + 4(n - 1) = 62 \\ 4(n - 1) = 60 \\ n - 1 = 15 \\ n = 16](https://tex.z-dn.net/?f=2%20%2B%204%28n%20-%201%29%20%3D%2062%20%5C%5C%204%28n%20-%201%29%20%3D%2060%20%5C%5C%20n%20-%201%20%3D%2015%20%5C%5C%20n%20%3D%2016)
Since n is a natural number, 62 belongs to the sequence.
Hence
![{8}^{62}](https://tex.z-dn.net/?f=%20%7B8%7D%5E%7B62%7D%20)
will have a unit digit of 4.
The answer is D
I hope that helps
I’m pretty sure the answer is c
Answer:
1.08
Step-by-step explanation:Simplify the radical by breaking the radicand up into a product of known factors.