Y = -2x - 3
First make a table, then start inserting the x's you choose and figure out the y's.
x y
----------------------
-2 -2(-2) -3
4 - 3
1
-----------------------
-1 -2(-1) - 3
2 - 3
-1
------------------------
0 -2(0) - 3
0 - 3
-3
-------------------------
1 -2(1) - 3
-2 - 3
-5
--------------------------
2 -2(2) - 3
-4 - 3
-7
--------------------------
Now you can plot the points into a graph.
(-2, 1), (-1, -1), (0, -3), (1, -5), (2, -7)
Answer:
2x+5
because you are subtracting it is basically multiplying (5x-6) by negative one so you have to distribute it out so you are basically adding (7x-1) and (-5x+6) by adding like terms you get 7x-5x= 2x and -1+6=5
so the answer is 2x+5
Answer:
(-14,-4)
Step-by-step explanation:
Given the pre-image A=(-7,-2)
If A is dilated with a scale factor of 2
Then the image of A,
A' = (-7,-2) X 2
We multiply each coordinate point by 2
=(-7*2,-2*2)=(-14,-4)
Therefore, the point A' would be: (-14,-4)
Answer:
The 95% CI is (6.93% , 7.47%)
The 99% CI is (6.85% , 7.55%)
Step-by-step explanation:
We have to estimate two confidence intervals (95% and 99%) for the population mean 30-year fixed mortgage rate.
We know that the population standard deviation is 0.7%.
The sample mean is 7.2%. The sample size is n=26.
The z-score for a 95% CI is z=1.96 and for a 99% CI is z=2.58.
The margin of error for a 95% CI is
![E=z\cdot \sigma/\sqrt{n}=1.96*0.7/\sqrt{26}=1.372/5.099=0.27](https://tex.z-dn.net/?f=E%3Dz%5Ccdot%20%5Csigma%2F%5Csqrt%7Bn%7D%3D1.96%2A0.7%2F%5Csqrt%7B26%7D%3D1.372%2F5.099%3D0.27)
Then, the upper and lower bounds are:
![LL=\bar x-z\cdot\sigma/\sqrt{n}=7.2-0.27=6.93\\\\ UL=\bar x+z\cdot\sigma/\sqrt{n} =7.2+0.27=7.47](https://tex.z-dn.net/?f=LL%3D%5Cbar%20x-z%5Ccdot%5Csigma%2F%5Csqrt%7Bn%7D%3D7.2-0.27%3D6.93%5C%5C%5C%5C%20UL%3D%5Cbar%20x%2Bz%5Ccdot%5Csigma%2F%5Csqrt%7Bn%7D%20%3D7.2%2B0.27%3D7.47)
Then, the 95% CI is
![6.93\leq x\leq 7.47](https://tex.z-dn.net/?f=6.93%5Cleq%20x%5Cleq%207.47)
The margin of error for a 99% CI is
![E=z\cdot \sigma/\sqrt{n}=2.58*0.7/\sqrt{26}=1.806/5.099=0.35](https://tex.z-dn.net/?f=E%3Dz%5Ccdot%20%5Csigma%2F%5Csqrt%7Bn%7D%3D2.58%2A0.7%2F%5Csqrt%7B26%7D%3D1.806%2F5.099%3D0.35)
Then, the upper and lower bounds are:
![LL=\bar x-z\cdot\sigma/\sqrt{n}=7.2-0.35=6.85\\\\ UL=\bar x+z\cdot\sigma/\sqrt{n} =7.2+0.35=7.55](https://tex.z-dn.net/?f=LL%3D%5Cbar%20x-z%5Ccdot%5Csigma%2F%5Csqrt%7Bn%7D%3D7.2-0.35%3D6.85%5C%5C%5C%5C%20UL%3D%5Cbar%20x%2Bz%5Ccdot%5Csigma%2F%5Csqrt%7Bn%7D%20%3D7.2%2B0.35%3D7.55)
Then, the 99% CI is
![6.85\leq x\leq 7.55](https://tex.z-dn.net/?f=6.85%5Cleq%20x%5Cleq%207.55)