Answer:
A kite with a 100 foot-long string is caught in a tree. When the full length of the string is stretched in a straight line to the ground, it touches the ground a distance of 30 feet from the bottom of the tree. Find the measure of the angle between the kite string and the ground.
17°
27°
63°
73°
Step-by-step explanation:
Answer:
Distance around the pool = 162.8 feet
Area of the pool = 957 square feet
Step-by-step explanation:
Distance around the swimming pool = Perimeter of the pool
Perimeter of the pool which is a composite figure will be,
= Circumference of the semicircle + Sum of three sides of the pool
= πr + 2×(length of the pool) + width of the pool
= 3.14×(10) + 2×40 + 20
= 62.8 + 80 + 20
= 162.8 ft
Area of the pool = Area of the semicircle + Area of the rectangular pool
= 
= 
= 157 + 800
= 957 square feet
Answer:
25 inches
Step-by-step explanation:
1. Information that is needed to solve the problem;
The formula for the perimeter is:
2(a+b) = P
where "a" is the length and "b" is the width.
2. Solving the problem;
Substitute the given values into the formula;
2( 5 + b ) = 58
Inverse operations;
2 ( 5 + b ) = 58
/2 /2
5 + b = 29
-5 -5
b = 25
Answer:
3) 5
4) 8.2
5) 6.8
6)FG = 6.4
7) EF = 3.6
8)DF = 4.8
Step-by-step explanation:
From the attached triangle, using trigonometric ratio we can find ∠G as; tan^(-1) (6/8)
Thus, ∠G = 36.87°
Still using trigonometric ratios;
FG/8 = cos 36.87°
FG = 8 cos 36.87°
FG = 6.4
3) EF + FG = EG
Since EG is 10, mean of EF and FG = 10/2 = 5
4) mean of EG and FG = (10 + 6.4)/2 = 8.2
5) EF + FG = EG
Thus; EF = EG - FG
EF = 10 - 6.4
EF = 3.6
Mean of EG and EF = (10 + 3.6)/2 = 6.8
6) FG = 6.4
7) EF = 3.6
8) Using trigonometric ratio;
DF/8 = sin 36.87
DF = 8 × 0.6
DF = 4.8