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2 years ago

9

Why can you use a model to check your answer for a division problem

1 answer:

aivan3 [116]2 years ago

7 0

If multiplication and retracing your track count as a model I believe it's good to see what you did wrong and to see what the answer really should bee

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What do you set each term equal to in order to solve for all of the "roots" of a function? No links please :)

Citrus2011 [14]

Answer:

Solving quadratic equations can be difficult, but luckily there are several different methods that we can use depending on what type of quadratic that we are trying to solve. The four methods of solving a quadratic equation are factoring, using the square roots, completing the square and the quadratic formula.

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

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finlep [7]

Step-by-step explanation:

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1 year ago

Madison is buying a $3,000 car at 9% simple interest for 2 years. What will be the total amount she pays for the car?

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Answer

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Step-by-step explanation:

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2 years ago

Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part

katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

$(26)x = 1$

$(50)x = 1$

and:

$(2^6)^x = 1$

$(5^0)^x = 1$

Solving: $(26)x = 1$ and $(50)x = 1$

$(26)x = 1$

Divide both sides by 26

$x = \frac{1}{26}$

$(50)x = 1$

Divide both sides by 50

$x = \frac{1}{50}$

Solving $(2^6)^x = 1$ and $(5^0)^x = 1$

$(2^6)^x = 1$

Express 1 as 2^0

$(2^6)^x = 2^0$

Remove bracket

$2^{6x} = 2^0$

Cancel out 2

$6x = 0$

Divide both sides by 6

$x = \frac{0}{6}$

$x = 0$

$(5^0)^x = 1$

Express 1 as 5^0

$(5^0)^x = 5^0$

Cancel out 5^0

$x = 1$

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2 years ago