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3 years ago

12

Rosa has a rectangular picture frame that measures 9 inches by 16 inches. What is the diagonal distance across the frame? You ma

y want to draw a sketch to help you solve the problem. Round your answer to the nearest tenth if necessary.

1 answer:

Sloan [31]3 years ago

3 0

72 is the correct answer

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Please answer this question now

Nookie1986 [14]

Answer:

Arc BC = 117°

Step-by-step explanation:

Angle D is an inscribed angle that intercepts arc ABC. According to the Inscribed angle theorem of a circle, m<D = ½ of arc ABC.

Thus,

104° = ½(AB + BC)

104° = ½(91° + BC)

Multiply both sides by 2

104*2 = 91 + BC

208 = 91 + BC

Subtract both sides by 91

208 - 91 = BC

117 = BC

Arc BC = 117°

4 0

3 years ago

How to convert angle in radians to degrees?

jek_recluse [69]

360° = 2π
2 = 360° / π
1 rad = 360° / 2π

3 0

4 years ago

1 + ( -6 ) = -3 + d how do i solve this

valentinak56 [21]

Is there any variables?

3 0

3 years ago

The marketing director of a large department store wants to estimate the average number of customers who enter the store every f

Dahasolnce [82]

Answer:

$36.5674\leq x'\leq61.4326$

Step-by-step explanation:

If we assume that the number of arrivals is normally distributed and we don't know the population standard deviation, we can calculated a 95% confidence interval to estimate the mean value as:

$x-t_{\alpha /2}\frac{s}{\sqrt{n} } \leq x'\leq x-t_{\alpha /2}\frac{s}{\sqrt{n} }$

where x' is the population mean value, x is the sample mean value, s is the sample standard deviation, n is the size of the sample, $\alpha$ is equal to 0.05 (it is calculated as: 1 - 0.95) and $t_{\alpha /2}$ is the t value with n-1 degrees of freedom that let a probability of $\alpha/2$ on the right tail.

So, replacing the mean of the sample by 49, the standard deviation of the sample by 17.38, n by 10 and $t_{\alpha /2}$ by 2.2621 we get:

$49-2.2621\frac{17.38}{\sqrt{10} } \leq x'\leq 49+2.2621\frac{17.38}{\sqrt{10} }\\49-12.4326\leq x'\leq 49+12.4326\\36.5674\leq x'\leq61.4326$

Finally, the interval values that she get is:

$36.5674\leq x'\leq61.4326$

8 0

3 years ago

How do I solve this?

Nutka1998 [239]

$\dfrac{2ab^2}{n}=y$ $\text{Solve for (a)}$

$2ab^2=yn
$ $\text{Multiply both sides by n}$

$ab^2= \dfrac{yn}{2}$ $\text{Divide both sides by 2}$

$a= \dfrac{yn}{2b^2}$ $\text{Divide both sides by}$ $b^2$

$\text{Hence solved}$

3 0

4 years ago