We have been given a quadratic function
and we need to restrict the domain such that it becomes a one to one function.
We know that vertex of this quadratic function occurs at (5,2).
Further, we know that range of this function is
.
If we restrict the domain of this function to either
or
, it will become one to one function.
Let us know find its inverse.

Upon interchanging x and y, we get:

Let us now solve this function for y.

Hence, the inverse function would be
if we restrict the domain of original function to
and the inverse function would be
if we restrict the domain to
.
At x = 0, y-coordinate is at -4 so that means f(0) = -4
Now for f(x) = 4, we need to find any x-coordinates such that y-coordinates is 4.
There are two possible answer: x = -8 and x = 8
So x = -8, 8
Hope this helps.
Answer:
745
Step-by-step explanation:
Answer:
V = 5(12)(7) which is F.
Step-by-step explanation:
V = LWH
L = 12
W = 5
H = 7
12 * 5 * 7
Answer:
the area of the shape is 7.14
Step-by-step explanation:
First, find the area of the square:
2 in x 2 in = 4 in
then to find the area of the semi- circles add them together to make a circle
To find the area of the circle, use:
pi x radius^2
Since the diameter is 2 divide the diameter by 2 to get radius
3.14 x 1^2 = 3.14
The circle is 3.14 plus 4 ( the square ) = 7.14