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3 years ago

Solve the compound inequality 6b 6

Mathematics

1 answer:

Zinaida [17]3 years ago

3 0

Answer:

<6 OR b>-3

Step-by-step explanation:

hope this helps

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What is the answer to this? PLEASE HELP!

Leno4ka [110]

12 inches in 1 foot
12*12*12 cubic inches in 1 cubic foot = 1728 in^2

So 7125 in^3 = 7125/1728 = 4.123 ft^3 to nearest thousandth

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3 years ago

Molecules of a toxic chemical eventually decompose into inert substances. Suppose the decomposition time is exponentially distri

koban [17]

Answer:

a) 4.16 years

b) 27.73 years

c) 238.44 years

d) 3,870.53 years

Step-by-step explanation:

Let X be the random variable that measures the decomposition time.

$\bf \lambda =6$

In this case, since the decomposition time is exponentially distributed with a mean of 1/6, we have

$\bf P(X\leq t)=1-e^{-t/6}\Rightarrow P(X>t)=1-(1-e^{-t/6})=e^{-t/6}$

and we must find a t such that P(x>t)=0.5.

$\bf P(X>t)=0.5\Rightarrow e^{-t/6}=0.5\Rightarrow -t/6=ln(0.5)\Rightarrow t=-6ln(0.5)=4.16\;years$

$\bf \lambda =40$

$\bf P(X>t)=0.5\Rightarrow e^{-t/40}=0.5\Rightarrow -t/40=ln(0.5)\Rightarrow t=-40ln(0.5)=27.73\;years$

$\bf \lambda =344$

$\bf P(X>t)=0.5\Rightarrow e^{-t/344}=0.5\Rightarrow -t/344=ln(0.5)\Rightarrow t=-344ln(0.5)=238.44\;years$

$\bf \lambda =5584$

$\bf P(X>t)=0.5\Rightarrow e^{-t/5584}=0.5\Rightarrow -t/5584=ln(0.5)\Rightarrow t=-5584ln(0.5)=3870.53\;years$

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4 years ago

The heights of women aged 20 – 29 in the United States are approximately Normal with mean 64.2 inches and standard deviation 2.8

Alenkinab [10]

Answer:

a) 0.64

b) -1.13

Step-by-step explanation:

We are given the following information in the question:

Women:

Mean, μ = 64.2 inches

Standard Deviation, σ = 2.8 inches

We are given that the distribution of heights of women is a bell shaped distribution that is a normal distribution.

Men:

Mean, μ = 69.4 inches

Standard Deviation, σ = 3.0 inches

We are given that the distribution of heights of men is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

5.5 feet = 66 inches

a) z‑score for a woman 5.5 feet tall

$x = 66\\\\\Rightqrrow z = \displaystyle\frac{66 - 64.2}{2.8} = 0.64$

b) z‑score for a man 5.5 feet tall

$x = 66\\\\\Rightqrrow z = \displaystyle\frac{66 - 69.4}{3.0} = -1.13$

4 0

3 years ago