The most distinctive feature of ape dentition, which clearly distinguishes apes from Old World monkeys, is a Y-5 molar pattern.
<h3>What is the Y-5 molar pattern?</h3>
- This is a distinctive type of molar teeth pattern found in apes and hominoids.
- In this, 5 cusps or raised surfaces are present on the grinding surface of teeth, roughly forming a Y- shape. Therefore, this is also known as Y-5 pattern.
- Whereas Old world monkeys have only 4 cusps on their lower molars present in a bilophodont pattern.
- A Y-5 molar is formed when the tooth is divided into different pieces which form the complete structure of the tooth.
- In bilophodont pattern the tooth is divided into 2 symmetric sections.
- The dental formula of apes is 2.1.2.3/2.1.2.3 i.e. 2 incisors, 1 canine, 2 premolars, 3 molars.
Learn more about dentition in apes here:
brainly.com/question/13375557
#SPJ1
The given statement is True.
The transport process that does not requires the consumption of ATP molecules is called as passive transport. The movement of solute molecules along the concentration gradient (from higher concentration to lower concentration) is called diffusion. This process does not requires ATP for the movement of molecules from one place to another.
Such plants are called vascular plants.
Answer:
a. Bands at 1kb, 6kb and 8kb
Explanation:
The EcoRI and BamHI are the restriction enzymes which cut the DNA sequence especially a plasmid at specific sites called the restriction sites.
The restriction enzymes produces bands of specific length therefore these restriction enzymes are used to estimate the approximate length of the DNA.
In the given question, the
1. EcoRI- produces two strands of 7 kb and 8 kb
2. BamHI- produces two strands of 1kb and 14kb
This shows that the length of DNA sequence is 15kb
But when the DNA strand are digested with both the enzymes simultaneously then it will produce three bands as:
i) 14 kb can be broken down in 2 bands of 6 kb and 8 kb
ii) 1 kb band is already produced by the Bam HI.
This shows that 1+6+8= 15 kb
Thus, Option-A is correct.
