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Paha777 [63]
3 years ago
9

Find the average rate of change over the given interval f(x) = 2^x , [3,5]

Mathematics
1 answer:
Vlada [557]3 years ago
4 0

Answer:

y=x*2^x (3,5)+y

Step-by-step explanation:

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Jeff's math grade is based on two quizzes, two tests, and one project. The table shows Jeff’s scores on these items, as well as
vazorg [7]

Answer:

Step-by-step explanation:

If you can post the table then I'lI be happy to help

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iogann1982 [59]

34.76

o

, nearly.

Explanation:

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3 years ago
H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.
natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

<h3>Given information-</h3>

The given function is,

h(x)=x^2+1

k(x)=x-2

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

(h+k)(x)=h(x)+k(x)

(h+k)(x)=x^2+1+x-2

(h+k)(2)=2^2+1+2-2

(h+k)(x)=5

2)The value of the function (h-k)(3),

(h-k)(x)=h(x)-k(x)

(h-k)(x)=x^2+1-x+2

(h-k)(3)=3^2+1-3+2

(h-k)(x)=9

3) The value of the function 3h(2)+2k(3)

3h(x)+2k(x)=3x^2+3+2x-2\times 2

3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2

3h(2)+2k(3)=17

Hence the value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

Learn more about the quadratic equation here;

brainly.com/question/2263981

4 0
3 years ago
13-yard gain please help
fgiga [73]

Answer:

+ 13?

i tried i apologize if its wrong idk what you ment

6 0
3 years ago
Solve: -11 = -2 + x/4
IrinaK [193]

Answer:

x = -36

Step-by-step explanation:

-11 + 2 = x/4

-9 = x/4

-9 * 4 = x

-36

8 0
3 years ago
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