A) x^2 +x -30 = 0 is factored by looking for two factors of 30 that differ by 1. We know ... 30 = 1*30 = 2*15 = 3*10 = 5*6The last two factors differ by 1, so we can factor the trinomial as (x +6)(x -5) = 0
b) The solutions are found by finding values of x that make these factors zero. The only way the product will be zero is if one or more of the factors is zero. x + 6 = 0 x = -6 . . . . . subtract 6
x - 5 = 0 x = 5 . . . . . add 5
The solutions are x = -6 or x = 5These are the values of x that will satisfy the equation (make it true). What they mean depends on the meaning of the variable and the situation the equation is a model of.
Answer:
2
Step-by-step explanation:
loge(x) is ln(x)
f(x) × ln(x)
Differentiate using product law
[ln(x) × f'(x)] + [(1/x) × f(x)]
x = 1
[ln(1) × f'(1)] + [(1/1) × f(1)]
(0 × 4) + (1 × 2)
0 + 2
2
Answer:
I tried my best to made the graph
3/-1/2
2/0/1
4/-2/3
2/0/1
1/+1/0
0/+2/1
12 and 13 have the same amount of students. so B or C will work. please mark brainliest
