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maxonik [38]
3 years ago
9

An exceptionally bright high school student has applied for two scholarships: a merit scholarship and an athletic scholarship. H

e estimates the following probabilities: The probability of getting the merit scholarship is 0.3 The probability of getting the athletic scholarship is 0.6 The probability of getting both scholarships is 0.08.
(a) What is the probability that he does not get the merit scholarship?
(b) What is the probability that he gets at least one of these scholarships?
Mathematics
1 answer:
9966 [12]3 years ago
4 0

Answer:

a) 0.70

b) 0.82

Step-by-step explanation:

a)

Let M be the event that student get merit scholarship and A be the event that student get athletic scholarship.

P(M)=0.3

P(A)=0.6

P(M∩A)=0.08

P(not getting merit scholarships)=P(M')=?

P(not getting merit scholarships)=1-P(M)

P(not getting merit scholarships)=1-0.3

P(not getting merit scholarships)=0.7

The probability that student not get the merit scholarship is 70%.

b)

P(getting at least one of two scholarships)=P(M or A)=P(M∪A)

P(getting at least one of two scholarships)=P(M)+P(A)-P(M∩A)

P(getting at least one of two scholarships)=0.3+0.6-0.08

P(getting at least one of two scholarships)=0.9-0.08

P(getting at least one of two scholarships)=0.82

The probability that student gets at least one of two scholarships is 82%.

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Answer:

h = 38

Step-by-step explanation:

\frac{h + 52}{70}  = \frac{9}{7}

h + 52 =  \frac{9}{7}  \times 70

h + 52 =  \frac{9 \times 70}{7}

h + 52 =  \frac{630}{7}

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the answer is 38.

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Evaluate-(3^5)(3^3) <br>​
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(3+(3)/(5))(3-(3)/(5))

Step-by-step explanation:

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25 feet in 4 seconds; 80 feet in x seconds write a proportion for each phrase and solve it​
ozzi

Answer:

12.8 seconds

Step-by-step explanation:

Create a proportion where x is the number of seconds for 80 feet

\frac{25}{4} = \frac{80}{x}

Cross multiply and solve for x

25x = 320

x = 12.8

So, the answer is 12.8 seconds

3 0
3 years ago
during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak
STatiana [176]
<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

f(t)=-16t^{2}+64t+4

Where,

a=-16\\b=64\\c=4

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0

Using the quadratic equation:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0

Finally, we can conclude that:

- The softball reach its maximum height at t equals to 2. (68 feet)

- The softball hits the ground at t equals to 4.0615 (0 feet)

- At t equals to 0, the height of the softball is equal to 4 feet.

See the attached image for the graphic.

Have a nice day!

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