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bazaltina [42]
3 years ago
9

In the diagram, find m angle BAC

Mathematics
1 answer:
LuckyWell [14K]3 years ago
7 0
I can't see the diagram. Did you attach the file?
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6th-grade math, fill out the table! :)
Svetradugi [14.3K]

Answer:

21 wins, table is attached.

Step-by-step explanation:

The ratio of 7 wins to 2 losses is 7:2. A ratio is just saying that every time one value is increased by 7, the other is increased by 2.

So we can fill out the table, in every iteration wins increases by 7 and losses increases by 2.

When we fill this out, we find that when losses is 6, wins is 21, so when you have 2 losses you have 21 wins.

Hope this helped!

4 0
3 years ago
Esceibir 5 oraciones con el analizis​
marishachu [46]

Answer:

a

a

a

a

bbbb

Step-by-step explanation:

6 0
4 years ago
You play a game that involves spinning a wheel. Each section of the wheel shown has the same area. Use a sample space to determi
Anastasy [175]

Answer:

is it fighet spinner or I am wrong hahahaa fighet spinner

7 0
3 years ago
Read 2 more answers
The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth
Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

(c) The probability that at least three of the selected computers are desktops is 0.401.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = P(Laptop) = p_{X} = \frac{4}{9}

The probability of selecting a desktop is = P(Desktop) = p_{Y} = \frac{5}{9}

Then both X and Y follows Binomial distribution.

X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})

The probability function of a binomial distribution is:

P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}

(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: {n\choose k}=\frac{n!}{k!(n-k)!}

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

{8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\  =0.304832\\\approx0.305

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

P(Y\geq 3)=1-P(Y

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0
3 years ago
The polynomial p(x) has factors of x-5 and x-8. Which must be correct ?
aleksandrvk [35]

Answer:

Find an answer to your question The polynomial p(x) has factors of x – 5 and x + 8. Which MUST be correct?

Step-by-step explanation:

If x – a is indeed a factor of p(x), then the remainder after division by x – a will be ... the polynomial (courtesy of the Remainder Theorem), but x – a is also a factor ... completed division: 2 2 5 0 7 ... x + 4 is a factor of 5x4 + 16x3 – 15x2 + 8x + 16.

8 0
3 years ago
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