Answer:
<u>The correct answer is r = ∛GM*T²/4π²</u>
Step-by-step explanation:
Let's rewrite the formula to find the period of orbit of a satellite around a planet, to solve for r, this way:
T^2=(4pi^2/GM)r^3
T² = (4π²/GM) * r³
r³ = T²/ (4π²/GM)
r³ = T² * GM/4π²
r³ = GMT²/4π²
∛r³ = ∛GM*T²/4π²
r = ∛GM*T²/4π²
<u>The correct answer is r = ∛GM*T²/4π²</u>
If C is the MIDPOINT of BD, and BD equals 12, then what does CD equal?
AD = AC+CD, so you only need to find length of CD and add length of AC (which you already have) to it.
Hope this helps
(10x4x5)+(5x5x5) because you could make 2 shapes out of it. one being a cude that is 5x5x5 and the other being a rectangle that is 4x10x5 thenyou would just add them together. :) hope that helps
Answer:
20
Step-by-step explanation:
Total no = 75
N (P) = 48 , N (H) = 45 , N (T) = 58
N (P∩H) = 28 , N (H∩T) = 37 , N (P∩T) = 40
N (P∩H∩T) = 25
Total no = N (P) + N (H) + N (T) - N (P∩H) - N (H∩T) - N (P∩T) + N (P∩H∩T) + neither
75 = 48 + 45 + 58 - 28 - 37 - 40 + 25 + neither
75 = 71 + neither → neither = 4
N (only P) = N (P) - N (P∩H) - N (P∩T) + N (P∩H∩T) = 48 - 28 - 40 + 25 = 5
N (only H) = N (H) - N (P∩H) - N (H∩T) + N (P∩H∩T) = 45 - 28 - 37 + 25 = 5
N (only T) = N (T) - N (H∩T) - N (P∩T) + N (P∩H∩T) = 58 - 37 - 40 + 25 = 6
So, total liking either one or neither = 4 + 5 + 5 + 6 = 20
1. 2x^2-x-15=0
A = 2
B = -1
C = -15
2. 10^2-2x=0
A = 10
B = -2
C = 0
3. x^2–3x-40=0
A = 1
B = -3
C = -40
4. x^2+3x-2=0
A = 1
B = 3
C = -2
5. 4x^2-17x+8=0
A = 4
B = -17
C = 8
Remember the equations should look like Ax^2+Bx+C=0 (in this order!!)
