Answer:
what do question I didn't get it
Answer:
KPF = 9 and H = 129
Step-by-step explanation:
An inscribed quadrilateral in a circle has all diagonal angles add up to 180, so we can use this to find the angles of the quadrilateral.
H= 180-EPK and K = 180-E so H = 129 and K = 60
Now PF and EH are parallel, so PE is a transversal. That means FPE = 180 - E = 60. Now it's pretty easy to solve for KPF = FPE - EPK = 60 - 51 = 9.
Let me know if you don't see how I did any of this and I'll be happy to explain it..
check the picture below, you can pretty much count the units off the grid.
recall that A = (1/2)bh.
1) y:10;
2) 4p+6q;
3) x +( x+ 1) = 59 => 2x = 58 => x = 29 => 29 and 30;
X+x+1+x+2=51
3x+3=51
Use inverse operations to solve
subtract 3 from both sides
3x=48
Divide by 3 on both sides
x=16
16, 17, 18
