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seraphim [82]
3 years ago
13

Find three consecutive integers whose sum is 51

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0
X+x+1+x+2=51

3x+3=51
Use inverse operations to solve

subtract 3 from both sides

3x=48 

Divide by 3 on both sides

x=16

16, 17, 18
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Choice B:
The line intersects at both points (0,-3) and (1,0)

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5 0
3 years ago
Can you guys help me with all 3 questions please would really appreciate it.
Temka [501]

Answer:

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Step-by-step explanation:

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3 0
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3 years ago
Kimiko works at the drive-thru window in a fast-food restaurant. At the end of a 2-hour shift, the display at her window shows t
Anastaziya [24]

Answer:

90 customers

Step-by-step explanation:

Total shift time  = 2 hours

1 hours = 60 minutes

Total shift time minutes = 2*60 minutes = 120 minutes

Average Time taken to serve 1 customer = 1 minute 20 seconds

lets convert  1 minute 20 seconds in fraction

60 seconds = 1 minute

20 seconds  = 20/60 minutes = 1/3 minutes

Thus,

Average Time taken to serve 1 customer = 1 minute + 1/3 minutes = 4/3 minutes

Lets assume she served x customer in her 2 hour shift

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3 0
3 years ago
Express 2x+1/(x-2)(x²+1) as a partial fraction.
Oduvanchick [21]

Answer:

Partial fraction = 1/(x-2) - x/(x^2+1)

Step-by-step explanation:

Question:

Express 2x+1/(x-2)(x²+1) as a partial fraction.

Note: it will be assumed that there was a typo in the interpretation of parentheses to mean

(2x+1) / ( (x-2)(x^2+1) )

Let

(2x+1) / ( (x-2)(x^2+1) ) = A/(x-2) + (Bx+C)/(x^2+1) .........................(0)

(2x+1) / ( (x-2)(x^2+1) ) = (A(x^2+1)+(Bx+C)(x-2)) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = (Ax^2+A+Bx^2+(C-2B)x-2C) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = ( (A+B)x^2+(C-2B)x+A-2C ) / ( (x-2)(B/(x^2+1) )

Match numerators

2x+1 = (A+B)x^2+(C-2B)x+A-2C

Match coefficients,

A+B = 0 ..................(1)

-2B+C = 2 .................(2)

A-2C = 1 ...................(3)

Solve for A, B and C

Substitute A from (1) in (3)

-B - 2C =1  

transpose and solve for B

B = -2C-1  ....................(4)

Substitue B from (4) in (2)

-2(-2C-1) + C = 2  

simplify

5C = 2-2 = 0

C=0  ..........................(5)

substitute (5)  in (4)

B = -2C-1 = -1  ...............(6)

Substitue (6) in (1)

A+(-1) = 0

A=1 .............................(7)

Using values from (7), (6) and (5) to substitute in (0)

we get

(2x+1) / ( (x-2)(x^2+1) ) = 1/(x-2) - x/(x^2+1)

as the required partial fraction

7 0
3 years ago
Read 2 more answers
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