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3 years ago

Elijah wants to fence in a rectangular play area in his backyard for his new puppies. He wants the length of

Mathematics

1 answer:

makkiz [27]3 years ago

8 0

$48 \div 4 = 12$

$12 - 4 = 8$

$12 \times 2 = 24$

$8 \times 2 = 16$

$24 + 16 = 40$

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Find the value of x to the nearest tenth.

Lana71 [14]

Answer:

x = 14.7

Step-by-step explanation:

Use Law of Sines.

7/sin20=x/sin46

cross multiply

7sin46=xsin20

divide both sides by sin20 to isolate x

x = 7sin46/sin20

x = 14.72

3 0

3 years ago

Solve for x. Round to the nearest tenth, if necessary.

pychu [463]

Answer:

x = 14

Step-by-step explanation.

First I would use sine to find x's value. So ----> sin(30) = 7/x ----> x sin(30) = 7 ----> x = 7/sin(30) = 14.

You Can also find that x is equal to 14 by applying the 30, 60, 90, triangle rule. Becuase '7' opposes the 30 degree angle it is 1/2 the hypotenuse, if thats the case just multiply the 7 by 2 and you have the hypotenuse length.

3 0

2 years ago

Answer 10,11 and 12 for 100 points

geniusboy [140]

10) 7(2m+3)
11) 3(3r-1)
12) 2p(5q+4)

3 0

3 years ago

Read 2 more answers

Slices of pizza for a certain brand of pizza have a mass that is approximately normally distributed with a mean of 67.7 grams an

Alexxx [7]

Answer:

a. s.e. = 0.338

b. The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 0.5871 or 58.71%

c. The probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams is 0.0694 or 6.94%

d. The sample mean of 62.75 would represent the 15th percentile

Step-by-step explanation:

1. Let's review the information provided to us to answer the question properly:

μ of the mass of slices of pizza for a certain brand = 67.7 grams

σ of the mass of slices of pizza for a certain brand = 2.28 grams

2. For samples of size 20 pizza slices, what is the standard deviation for the sampling distribution of the sample mean?

Let's recall that the standard deviation of the sampling distribution of the mean is called the standard error of the mean and its formula is:

μσs.e.= √σ/n, where n is the sample size.

s.e. = √2.28/20

s.e. = 0.338

3. What is the probability of finding a random slice of pizza with a mass of less than 67.2 grams?

Let's find the z-score for X = 67.2, this way:

z-score = (X - μ)/σ

z-score = (67.2 - 67.7)/2.28

z-score = 0.5/2.28

z-score = 0.22 (rounding to the next hundredth)

Now, using the z-table, let's find p, the probability:

p (z = 0.22) = 0.5871

The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 58.71%

4. What is the probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams?

Let's use the central limit theorem to find the z-score, this way:

z-score = X - μ/s.e

z-score = 67.2 - 67.7/0.338

z-score = -0.5/0.338

z-score = - 1.48

Now, using the z-table, let's find p, the probability:

p (z = -1.48) = 0.0694

5. What sample mean (for a sample of size 20) would represent the bottom 15% (the 15th percentile)?

For p = 0.150, let's find the z-score:

z-score = - 2.17

z-score = X - μ/s.e

- 2.17 = (X - 67.7)/2.28

- 4.95 = X - 67.7

X = 67.7 - 4.95

X = 62.75 (rounding to the next hundredth)

The sample mean of 62.75 would represent the 15th percentile

7 0

3 years ago

Help on this please!

Nana76 [90]

2/9 - 7/12

First, multiply to find a common denominator. Multiply both pieces of the left fraction by 12, and both pieces of the right fraction by 9.

24/108 - 63/108 = -39/108 = -13/36

a= -13
b= 36

8 0

3 years ago