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3 years ago

Math help please TY :3 HWAJDSK 10 POINTS REWARDING !!

Mathematics

1 answer:

valkas [14]3 years ago

7 0

I will do Point A carefully, The others I will indicate. Start with the Given Point A. Then do the translations

A(-1,2) Original Point

Reflection: about x axis:x stays the same; y becomes -y:Result(-1,-2)

T<-3,4>: x goes three left, y goes 4 up (-1 - 3, -2 + 4): Result(-4,2)

R90 CCW: Point (x,y) becomes (-y , x ) So (-4,2) becomes(-2, - 4): Result (-2, - 4)

B(4,2) Original Point

Reflection: (4, - 2)
T< (-3,4): (4-3,-2 + 4): (1 , 2)
R90 CCW: (-y,x) = (-2 , 1)

C(4, -5) Original Point

Reflection (4,5)
T<-3,4): (4 - 3, 5 + 4): (1,9)
R90, CCW (-9 , 1)

D(-1 , -5) Original Point

Reflection (-1,5)
T(<-3,4): (-1 - 3, 5 + 4): (-4,9)
R90, CCW ( - 9, - 4)

Note: CCW means Counter Clockwise

The graph on the left is the same one you have been given.

The graph on the right is the same figure after all the transformations

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Allie ordered a set of green and yellow pins. She received 28 green pins and 7 yellow pins. What percentage of the pins were gre

klio [65]

Answer:

80%

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3 years ago

4 in.

sleet_krkn [62]

Answer:

305.12 square inches

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The area of the window is equal to the area of a rectangle, plus the area of two quarter circles plus the area of the smaller square between the two upper corners

Find the area of rectangle

$A=(12)(26-4)=264\ in^2$

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$A=2[\frac{1}{4}(3.14)(4^2)]$

$A=25.12\ in^2$

Find the area of the smaller square between the two upper corners

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$A=264+25.12+16=305.12\ in^2$

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3 years ago

Please Help!!! I give a medal to anyone to tries!!!

poizon [28]

Well, the way I see it is that both Mr. Romano, and Ms. Guerra are correct but Professor McCoy is incorrect because he said (x+2) when it should be (x-2).

The factor theorem states that:
If f(a)=0, then (x-a) is a factor

The remainder theorem states that:
If (x-a) is a factor of f(x), then f(x) / (x-a) = 0

So if 2 is indeed a zero of f(x), then a factor must be (x-2) according to the fist which supports Ms. Guerra and also if (x-2) is indeed a factor as Ms. Guerra says then we know that f(x) / (x-a) = 0 which supports Mr. Romano

Professor McCoy is wrong because he used (x + 2) when it should be (x-2). I know this because according to the factor theorem if f(a)=0, then (x-a) is a factor. And the remainder theorem says if (x-a) is a factor of f(x), then f(x)/x-a =0.

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3 years ago