13: answer: 5 9/16
16: answer: 8 1/10
Answer:
- rational
- irrational
- irrational
- irrational
- √7, it is irrational
Step-by-step explanation:
A <em>rational</em> number is one that can be expressed as the ratio of two integers. All fractions that have integer numerators and (non-zero) denominators are <em>rational</em> numbers. Any finite decimal number, or any repeating decimal number, is a rational number. These can always be expressed as the ratio of two integers. For example, 0.4040... = 40/99, and 0.286 = 286/1000.
To make an irrational sum, at least one of the contributors must be irrational. You want an irrational 2-number sum that has 7/8 as one of the contributors. Since 7/8 is rational, the other contributor must be irrational.
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<u>Step 1</u>. The number 7/8 is <em>rational</em>.
<u>Step 2</u>. The desired sum is <em>irrational</em>.
<u>Step 3</u>. The rule <em>rational + </em><em>irrational</em><em> = irrational</em> applies.
<u>Step 4</u>. An <em>irrational</em> number must be chosen.
Step 5. √7 will produce an irrational sum, because <em>it is irrational</em>.
Answer:
c
Step-by-step explanation:
Answer:
a) x = 62
b) x = 33
Step-by-step explanation:
Hi there!
a) Let´s write the equation:
√(2x-3) = 11
Square both sides
2x - 3 = 121
add 3 to both sides of the equation
2x = 124
divide by 2 both sides
x = 62
Let´s check:
√(2x-3) = 11
x = 62
√(2(62)-3) = 11
√(124-3) = 11
√121 = 11
11 = 11
x = 62 satisfies the equation
b) Let´s write the equation:
∛(6 - x) = -3
Cube both sides
6 - x = -27
subtract 6 to both sides
-x = -27 - 6
-x = -33
divide by -1 both sides
x = 33
Now, let´s check the result:
∛(6 - x) = -3
x = 33
∛(6 - 33) = -3
∛(-27) = -3
-3 = -3
x = 33 satisfies the equation
Word form- seven hundred and one thousand two hundrend and forty five
standard form - 700,000 + 1,000 + 200 + 40 + 5
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