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BigorU [14]
3 years ago
8

SOlve the equation 0.25 r - 0.125 + 0.5 r = 0.5 +r

Mathematics
1 answer:
seropon [69]3 years ago
6 0
You put all the numbers on one side of the equation and letters on another. 

0.25r + 0.5r - r = 0.5 +0.125 

-0.75r  = 0.625    divide both sides by -0.75

r = -0.125


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Plz can someone help me out with both questions
alukav5142 [94]
1. Function
2. Not Function
4 0
3 years ago
This is due today, and I have no idea what I'm doing, please help if you know anything.
defon

Binomial distribution formula: P(x) = (n  k) p^k * (1 - p)^n - k

a) Probability that four parts are defective = 0.01374

P(4 defective) = (25 4) (0.04)^4 * (0.96)^21

P(4 defective) = 0.01374

b) Probability that at least one part is defective = 0.6396

Find the probability that 0 parts are defective and subtract that probability from 1.

P(0 defective) = (25 0) (0.04)^0 * (0.96)^25

P(0 defective) = 0.3604

1 - 0.3604 = 0.6396

c) Probability that 25 parts are defective = approximately 0

P(25 defective) = (25 25) (0.04)^25 * (0.96)^0

P(25 defective) = approximately 0

d) Probability that at most 1 part is defective = 0.7358

Find the probability that 0 and 1 parts are defective and add them together.

P(0 defective) = 0.3604 (from above)

P(1 defective) = (25 1) (0.04)^1 * (0.96)^24

P(1 defective) = 0.3754

P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358

e) Mean = 1 | Standard Deviation = 0.9798

mean = n * p

mean = 25 * 0.04 = 1

stdev = \sqrt{np(1-p)}

stdev = \sqrt{(25)(0.04)(1-0.04)} = 0.9798

Hope this helps!! :)

7 0
3 years ago
Is (x+1) a factor off (x)=x3+x2−4x−4? <br><br> A) Yes<br> B) No
satela [25.4K]

Remainder theorem again...

p(x)=x^3+x^2-4x-4

p(-1)=(-1)^3+(-1)^2-4(-1)-4=0

So Yes, x+1 is a factor.

4 0
3 years ago
Read 2 more answers
HELP!! GEOMETRY
faust18 [17]

Answer:

you just rotate the

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What are the roots of the equation 9x^2 + 54x +82 = 0 in simplest a + bi form?​
s344n2d4d5 [400]

Answer:

The roots are

<h3>x =  - 3 +  \frac{1}{3}  i \:  \:  \: or \:  \:  \: x =  - 3 -  \frac{1}{3} i \\</h3>

Step-by-step explanation:

9x² + 54x + 82 = 0

Using the quadratic formula

That's

<h3>x =  \frac{ - b\pm \sqrt{ {b}^{2}  - 4ac} }{2a}</h3>

From the question

a = 9 , b = 54 , c = 82

Substitute the values into the above formula and solve

That's

<h3>x =  \frac{ - 54\pm \sqrt{ {54}^{2}  - 4(9)(82)} }{2(9)}  \\ x =  \frac{ - 54\pm \sqrt{2916 - 2952} }{18}  \\ x =  \frac{ - 54\pm \sqrt{ - 36} }{18}  \\ x =  \frac{ - 54\pm 6i}{18}</h3>

Separate the real and imaginary parts

That's

<h3>x =  -  \frac{54}{18} \pm \frac{6}{18}  \: i \\ x =  - 3\pm \frac{1}{3} i</h3>

We have the final answer as

<h3>x =  - 3 +  \frac{1}{3}  i \:  \:  \: or \:  \:  \: x =  - 3 -  \frac{1}{3} i \\</h3>

Hope this helps you

5 0
3 years ago
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