Question

A solution has a volume of 2.0 L and contains 36.0 g of glucose. If the molar mass of glucose is 180 g/mol, what is the molarity of the solution?

Answer 1

C(Molarity)=n(mole of solute)/V(L of solution)

36g/(180g/mol) = 0.2mol of glucose

C = 0.2mol/2L = 0.1M(mol/L)

Answer 2

Answer:- Molarity of the glucose solution is 0.1M.

Solution:- Molarity is moles of solute per liter of the solution.

From given info, 36.0 grams of glucose are present in a 2.0 L solution. We need to convert the grams to moles using molar mass and then divide the moles by the liters to get the molarity.

First step, grams to moles conversion:

$36.0g(\frac{1 mol}{180 g})$

= 0.2 mol

Second step, calculations for molarity:

molarity = $\frac{0.2 mol}{2.0 L}$

= 0.1M

(where, M stands for molarity)

So, the molarity of the glucose solution is 0.1M.