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SIZIF [17.4K]
3 years ago
14

What is the best description of what Becquerel observed in his experiment?

Chemistry
2 answers:
myrzilka [38]3 years ago
5 0

The answer is: D.unstable nuclei emitting high-energy particles as they formed more stable compositions.

Those high-energy particles are alpha particles , beta particles , gamma radiation.

For example, the decay chain of ²³⁸U is called the uranium series.

Decay start with U-238 and ends with Pb-206. There are several alpha and beta minus decays.

Antoine Henri Becquerel (1852 – 1908) was a French physicist and the first person to discover evidence of radioactivity.

Becquerel wrapped fluorescing crystal (uranium salt potassium uranyl sulfate) in a cloth, along with the photographic plate and a copper Maltese cross.

Several days later, he discovered that a image of the cross appeared on the plate.

The uranium salt was emitting radiation.

Because of this discovery, Becquerel won a Nobel Prize for Physics in 1903, which he shared with Marie Curie and Pierre Curie.


Contact [7]3 years ago
5 0
<h3><u>Answer</u>;</h3>

D.unstable nuclei emitting high-energy particles as they formed more stable compositions

<h3><u>Explanation</u>;</h3>
  • <u>Henri Becquerel</u> was a French physicist best known for his work on radioactivity, for which he won a Nobel Prize in 1903.
  • He accidentally found that a uranium-rich mineral emitted invisible, penetrating rays that could darken a photographic plate, a process called nuclear radioactivity.
  • <em><u>He found that radiation is associated with certain elements such as Uranium, whose nuclei is unstable. Unstable nuclei undergo radioactivity, where the emit high-energy particles to form more stable compositions.</u></em>
  • <em><u>Additionally, the process of radioactivity is not affected by factors such as temperature, pressure of ionization state of the unstable nuclei such as Uranium.</u></em>
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Answer:

The answer to your question is: letter c (96%)

Explanation:

Indium -113 (112-9040580 amu) ₁₁₃In

Indium-115 (114.9038780 amu)  ₁₁₅In

Atomic mass of Indium is 114.82 amu ₁₁₄.₈₂In

Formula

Atomic mass = m₁(%₁) +m₂(%₂)  / 100

%₁ = x I established this is an equation

%₂ = 100 - x

Substituting values

114.82 = 112.8040x + 114.9039(100-x) /100    and know we expand and simplify

114.82 = 112.8040x + 11490.39 - 114.9039x  /100

11482 = 112.8040x -114.9039x +11490.39

11482 - 11490.39 = 112.8040x -114.9039x

-8.39 = -2.099x

x = 3.99

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