Answer:
pH = 2.32
Explanation:
H2A + H2O -------> H3O+ + HA-
Ka2 is very less so i am not considering that dissociation.
now Ka = 8.0×10−5
= [H3O+] [HA-] / [H2A]
lets concentration of H3O+ = X then above equation will be
8.0×10−5 = [X] [X] / [0.28 -X]
8.0×10−5 = X2 / [0.28 -X]
X2 + 8.0×10−5 X - 2.24 x 10−5
solve the quardratic equation
X =0.004693 M
pH = -log[H+}
= -log [0.004693]
= 2.3285
≅2.32
pH = 2.32
Answer:
2×10² cg
Explanation:
We'll begin by converting each of the above to the same unit of measurement.
In this case, we shall convert each of the above to kg. This can be obtained as follow:
Conversion of cg to kg
1 cg = 1×10¯⁵ Kg
Therefore,
2×10² cg = 2×10² × 1×10¯⁵
2×10² cg = 0.002 kg
Conversion of dg to Kg
1 dg = 1×10¯⁴ kg
Therefore,
10 dg = 10 × 1×10¯⁴
10 dg = 0.001 kg
Conversion of mg to kg.
1 mg = 1×10¯⁶ Kg
Therefore,
2×10² mg = 2×10² × 1×10¯⁶
2×10² mg = 0.0002 kg
Conversion of ng to kg
1 ng = 1×10¯¹² kg
Therefore,
1×10⁵ ng = 1×10⁵ × 1×10¯¹²
1×10⁵ ng = 0.0000001 Kg
Summary
1. 2×10² cg = 0.002 kg
2. 10 dg = 0.001 kg
3. 2×10² mg = 0.0002 kg
4. 0.001 kg
5. 1×10⁵ ng = 0.0000001 Kg
From the above calculation, 2×10² cg is the highest mass.
Answer:
Las bebidas gaseosas como las gaseosas están hechas de un soluto de dióxido de carbono gaseoso en un líquido. La solubilidad del dióxido de carbono en el líquido depende de la presión y la temperatura de la lata de refresco, y también de agitar la lata de refresco que introduce burbujas que permanecen ocultas hasta que se abre la lata antes de que burbujee.
Por lo tanto, dado que la presión en la lata de refresco permanece constante, elevar la temperatura, agitar la lata de refresco o congelar el refresco, lo que aumenta la cantidad de dióxido de carbono en la porción líquida, hará que el refresco forme espuma y se derrame.
Explanation:
Answer:
0.049 mol/L.s
Explanation:
The decomposition of hydrogen peroxide is:
![Rate = -\dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{ 2 \Delta [H_2O_2]}{\Delta t}](https://tex.z-dn.net/?f=Rate%20%3D%20-%5Cdfrac%7B%5CDelta%20%5BH_2O_2%5D%7D%7B%5CDelta%20t%7D%3D%20%5Cdfrac%7B%5CDelta%20%5BH_2O_2%5D%7D%7B%5CDelta%20t%7D%3D%20%5Cdfrac%7B%202%20%20%5CDelta%20%5BH_2O_2%5D%7D%7B%5CDelta%20t%7D)
The rate of decomposition reaction = the rate of formation of 
= 0.098 mol/L.s
∴
Rate of formation of 
= 0.049 mol/L.s
