Answer:
22.13g
Explanation:
We'll begin by writing a balanced equation for the reaction. This is illustrated below:
2C2H2 + 5O2 —> 4CO2 + 2H2O
Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:
Molar Mass of C2H2 = (12x2) + (2x1)
= 24 + 2 = 26g/mol
Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g
Molar Mass of O2 = 16x2 = 32g/mol
Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g
Now, we can obtain the mass of C2H2 that will react with 68.1g of O2 as follow:
From the balanced equation above,
52g of C2H2 reacted with 160g of O2.
Therefore, Xg of C2H2 will react with 68.1g of O2 i.e
Xg of C2H2 = (52x68.1)/160
Xg of C2H2 = 22.13g
Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2
