All categories

4 years ago

PLS ANSWER F A S T

Physics

1 answer:

Marizza181 [45]4 years ago

7 0

Just so you know people aren’t replying because the bar graph isn’t show :/

You might be interested in

What organs make up the skeletal system

USPshnik [31]

Bones. The most important organ of the skeletal system is the bones.

Ligaments and Joints. Another important component, i.e. the ligaments are made of fibrous collagen tissue that attaches one bone to another bone.

Cartilage.

5 0

4 years ago

Read 2 more answers

What can scientist learn from studying sedimentary rocks?

cricket20 [7]

They are made of rocks

7 0

3 years ago

Read 2 more answers

An automobile traveling along a straight road increases its speed from 72 ft/s to 84 ft/s in 180 ft. if the acceleration is cons

Nikolay [14]

The equation that would allow us to calculate for the acceleration given the distance is written below,

a = (Vf² - Vo²) / 2d

where a is the acceleration, Vf is the final velocity, Vo is the initial velocity, and d is distance.

Substituting the known values,
a = ((84 ft/s)² - (72 ft/s)²) / 2(180 ft) = 5.2 ft/s²

Then, the equation that would relate the initial velocity, distance, acceleration and time is calculated through the equation,

d = Vot + 0.5at²

Substituting the known values,
180 = 72(t) + 0.5(5.2)(t²)

The value of t from the equation is 2.3 s

ANSWER: 2.3 s

5 0

4 years ago

A racing car whose mass is 1.2 X 10^3 kg is travelling at 8.9 m/s. It stops with a constant deceleration in a distance of 1.8X10

Alexeev081 [22]

given that initial speed of the car is

$v_i = 8.9 m/s$

now after travelling the distance d = 1.8 * 10^1 m the car will stop

so here we can use kinematics to find the acceleration of car

$v_f^2 - v_i^2 = 2 a d$

$0 - 8.9^2 = 2 a d$

here we have

$- 79.21 = 2*(18)*a$

$a = -2.2 m/s^2$

net force applied due to brakes of car is given by Newton's II law

$F = ma$

here we have

mass = 1.2 * 10^3 kg

$F_{net} = 1.2 * 10^3 * 2.2$

$F_{net} = 2.64 * 10^3 N$

now we can say

$F_{net} = F_1 + F_2$

$2.64 * 10^3 = 1.8 * 10^3 + F_2$

$F_2 = 8.4 * 10^2 N$

So the force applied due to brakes is given as above

7 0

3 years ago

If a resultant vector is 12 m/s and the horizontal component is 9 m/s, what is the value of the vertical component? A. 5.8 m/s B

horrorfan [7]

The vertical component is B) 7.9 m/s

Explanation:

A vector can be resolved into its horizontal and vertical components. The horizontal and the vertical components form the sides of a right triangle, in which the resultant corresponds to the hypothenuse, so we can use Pythagorean's theorem:

$R=\sqrt{R_x^2+R_y^2}$

where

R is the resultant vector

Rx is the horizontal component

Ry is the vertical component

In this problem, we have:

R = 12 m/s is the resultant vector

Rx = 9 m/s is the horizontal component

Solving the formula for Ry, we find the vertical component:

$R_y = \sqrt{R^2-R_x^2}=\sqrt{12^2-9^2}=7.9 m/s$

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

3 0

3 years ago