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Vera_Pavlovna [14]
3 years ago
9

Can you please answer

Mathematics
1 answer:
-Dominant- [34]3 years ago
5 0
It’s 500.
Explanation: If you would solve for that m^3 over m^2, you’d get m^1. So, m^1 is the square root of m^2, so you just take the square root of 250,000 to get 500. I really hope this helps!
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A company makes batteries with an average life span of 300
aksik [14]

Answer:

a) P(z<-0.66) = 0.2546

b) P(-1<z<1) = 0.6826

c) P(z>1.33) = 0.9082

Step-by-step explanation:

Mean = 300

Standard Deviation = 75

a) Less than 250 hours

P(X<250)=?

z = x - mean/ standard deviation

z = 250 - 300 / 75

z = -50/75

z = -0.66

P(X<250) = P(z<-0.66)

Looking for value of z = -0.66 from z score table

P(z<-0.66) = 0.2546

b. Between 225 and 375 hours

P(225<X<375)=?

z = x - mean/ standard deviation

z = 225-300/75

z = -75/75

z = -1

z = x - mean/ standard deviation

z = 375-300/75

z = 75/75

z = 1

P(225<X<375) = P(-1<z<1)

Looking for values from z score table

P(-1<z<1) = P(z<1) - P(z<-1)

P(-1<z<1) = 0.8413 - 0.1587

P(-1<z<1) = 0.6826

c. More than 400 hours

P(X>400) =?

z = x - mean/ standard deviation

z = 400-300/75

z = 100/75

z = 1.33

P(X>400) = P(z>1.33)

Looking for value of z = 1.33 from z-score table

P(z>1.33) = 0.9082

3 0
3 years ago
Please help<br> 100 point question!!
Nataly [62]

Can't see the Questions so It would help. Please Could you check out my questions that have not been answered thanks.

4 0
3 years ago
Read 2 more answers
Over the past year, your friend Maura has been saving up for an epic road trip to travel across the country this summer. Her goa
Misha Larkins [42]
<span>"Give an example of a sound financial decision Maura might make to support this goal. Why is it sound?"
<span>
</span>She could choose to carefully budget her trip and avoid overspending at all costs. This prevents going into debt. She should also save up extra money in the event of an emergency.

</span><span>Then give an example of a poor financial decision Maura might make considering her goal. Why is it a poor decision?</span><span>

Not having a plan would be a poor decision on her part. She could end up spending too much and not realize how much money she has left.


I hope I helped!
</span>
8 0
3 years ago
Wionna needs to average 5.8 from 14 judges. The mean score from 13 judges is 5.9. What is the lowest score she can receive from
kirill115 [55]
(5.9*13+s)/(13+1)\geq5.8

(76.7+s)/14\geq5.8

76.7+s\geq81.2

s\geq4.5
5 0
3 years ago
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According to Brad, consumers claim to prefer the brand-name products better than the generics, but they can't even tell which is
max2010maxim [7]

Answer:

a. There is not enough evidence to support the claim that the proportion that correctly identifies the chip is significantly smaller than 50%.

b. Test statistic z=-1.001

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that the proportion that correctly identifies the chip is significantly smaller than 50%.

Then, the null and alternative hypothesis are:

H_0: \pi=0.5\\\\H_a:\pi

The significance level is 0.01.

The sample has a size n=199.

The sample proportion is p=0.462.

p=X/n=92/199=0.462

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.5*0.5}{199}}\\\\\\ \sigma_p=\sqrt{0.001256}=0.035

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.462-0.5+0.5/199}{0.035}=\dfrac{-0.035}{0.035}=-1.001

This test is a left-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z

As the P-value (0.16) is greater than the significance level (0.01), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the proportion that correctly identifies the chip is significantly smaller than 50%.

7 0
4 years ago
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