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3 years ago

Solve for x:7x + 3 = 17

Mathematics

2 answers:

solong [7]3 years ago

5 0

X would have to equal 2 because when you multiply that by 7 you get 14 then add 3 and you get 17

seropon [69]3 years ago

5 0

Solve for x: 7x + 3 = 17

x = 2

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David is making patterns using these rules. Rule for Pattern A: start with 20 and subtract 2 Rule for Pattern B: start with 10 a

pochemuha

Answer:

20,18,16,14,12,10,8,6,4,2

10,9,8,7,6,5,4,3,2,1

Step-by-step explanation:

Pattern A:

Rule : start with 20 and subtract 2

Pattern B:

Rule : Start with 10 and subtract 1

Pattern 1:

20 - 2 = 18

18 - 2 = 16

16 - 2 = 14

14 - 2 = 12

12 - 2 = 10

10 - 2 = 8

8 - 2 = 6

6 - 2 = 4

4 - 2 = 2

20,18,16,14,12,10,8,6,4,2

Pattern 2:

10 - 1 = 9

9 - 1 = 8

8 - 1 = 7

7 - 1 = 6

6 - 1 = 5

5 - 1 = 4

4 - 1 = 3

3 - 1 = 2

2 - 1 = 1

10,9,8,7,6,5,4,3,2,1

5 0

2 years ago

2(3²+4²)=? WHATS THE ANSWER

yulyashka [42]

Answer:

Step-by-step explanation:

P- Parenthesis

E- Exponents

M- Multiplication

D- Division

A- Addition

S- Subtraction

(3²+4²)

3*3= 9 4*4= 16 16+9= 25 2(25) 25*2= 50

Hope this helped! (ﾉ◕ヮ◕)ﾉ*:･ﾟ✧

( ﾟдﾟ)つ Bye

7 0

2 years ago

How to work out an angle using cosine. three sides are; 8,19,12.

Kay [80]

To solve for cos use
adjacent over hypotenuse
divide the lengths of the sides
adj. / hyp.

7 0

3 years ago

47/7 as a mixed number in siplest form

puteri [66]

For this fraction, you would have to see how many times 7 goes into 47. So, 6 times as 7 times 6 is 42. Subtract 42 from 47, and this would be your remainder:

6 $\frac{5}{7}$

7 0

3 years ago

Read 2 more answers

A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The

Vladimir [108]

Using the Sine rule,

$\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}$ $\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}$

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

$A^0+P^0+B^0=180^0$ $\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}$

Using the side rule to find the length of wire BP,

$\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}$

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

4 0

1 year ago