3 years ago

Math Plz Help. Please graph with two points! explain how you found your answer

1 answer:

3 0

X intercept: y = 0
y= -3/4x -4
0 = -3/4 x - 4
4= -3/4 x
4 • -4/3 = x
-5.3 = x
y intercept: x = 0
y = -3/4 x -4
y = -3/4 (0) -4
y = -4
the points are (-5.3, 0) and (0, -4)

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6 points

kodGreya [7K]

Answer:

$y=-2\,(x+3)^2-3$

Step-by-step explanation:

Notice that they are asking you to write the equation of the parabola in vertex form, that is using the coordinates of the vertex $(x_v,y_v)$ in the expression:

$y-y_v=a\,(x-x_v)^2\\y=a\,(x-x_v)^2+y_v$

we can start by directly replacing the given vertex coordinates (-3, -3) in the expression, and then using the extra info on the point the parabola goes through in order to find the parameter $a$ :

$y=a\,(x-x_v)^2+y_v\\y=a\,(x+3)^2+(-3)\\y=a\,(x+3)^2-3\\-5=a\,(-2+3)^2-3\\-5=a\,(1)-3\\a=-5+3\\a=-2$

So, now we can write the full expression for the parabola:

$y=a\,(x+3)^2-3\\y=-2\,(x+3)^2-3$

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