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STatiana [176]
3 years ago
11

Solve the equation 4y-1.9=6.3

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
5 0
I’ve attached my work...
Hope this helps!

ruslelena [56]3 years ago
5 0
Y = 2.05 is the answer
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Start to finish must use all boxes, cant go diagonally
aleksandr82 [10.1K]

start at the top and go down one then go to the right and the vice verse

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8 0
3 years ago
How do i solve this equation? and could you show it to me step by step?
ipn [44]
The answer is 8 and yea it’s 2 steps first u have to remove the constant so u subtract 74-2=72 and 2-2=0. After u get rid of the constant u divide both sides by 9 basically 72/9 and 9/9 which is 8. So n is equal to 8 I hope this helped. I know it can be confusing
4 0
3 years ago
-19x + 23x = 44 what is x
matrenka [14]

Step-by-step explanation:

- 19 x + 23 x = 44

4x = 44

x = 44/ 4

x = 11

Hope it will help :)

6 0
3 years ago
Read 2 more answers
Please help me immediately ​
saw5 [17]

Answer:

756

Step-by-step explanation:

In the last question the volume of the tank was 168 m³

so to find the cost multiply 168 and 4.5

  • 168*4.5 =756

it will cost 756

7 0
3 years ago
Read 2 more answers
If f(x)=ln x and g(x)=e^x+1 find f(g(2))-g(f(e)) please help!!
Readme [11.4K]

Answer:

<h3>ln (e^2 + 1) - (e+ 1)</h3>

Step-by-step explanation:

Given f(x) = ln and g(x) = e^x + 1 to get  f(g(2))-g(f(e)), we need to first find the composite function f(g(x)) and g(f(x)).

For f(g(x));

f(g(x)) = f(e^x + 1)

substitute x for e^x + 1 in f(x)

f(g(x)) = ln (e^x + 1)

f(g(2)) = ln (e^2 + 1)

For g(f(x));

g(f(x)) = g(ln x)

substitute x for ln x in g(x)

g(f(x)) =  e^lnx + 1

g(f(x)) = x+1

g(f(e)) = e+1

f(g(2))-g(f(e)) = ln (e^2 + 1) - (e+ 1)

5 0
3 years ago
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