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EastWind [94]
3 years ago
14

If a permanent magnet is dropped or struck by a hammer, it may loose it's magnetism. Explain why.

Physics
1 answer:
Rainbow [258]3 years ago
8 0
This is because strong vibrations will affect the alignment of the magnetic domains within the magnetic material. The domains would change the alignment thus affecting the strength of the magnets which solely depends on the alignment of the domains. The strength of a magnet is the sum of the magnetic fields of all the domains in the magnet. Therefore, the net result will be a weaker magnet or the magnet loosing its magnetism.
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A concrete highway is built of slabs 12 m long (20°C). How wide should the expansion cracks between the slabs be (at 20°C) to pr
Bezzdna [24]

Answer:

0.001152m

Explanation:

Linear expansivity of a material is the change in length of the material per unit length per degree rise in temperature. Mathematically,

¢ = ∆L/L1∆°C

¢ is the linear expansivity of the material = 12 x 10⁻⁶ °C⁻¹

Where ∆L is the change in length = L2-L1

L2 is the final length = ?

L1 is the initial length = 12m

∆°C is the change in temperature = °C2 - °C1 = 50-(-30) = 80°C

Substituting this values inside the formula to get the final length L2 after expansion, we have;

12 x 10⁻⁶ °C⁻¹ = L2-12/12×80

12 x 10⁻⁶ °C⁻¹ = L2-12/960

L2-12= 960×12 x 10⁻⁶ °C⁻¹

L2-12 = 0.001152

L2 = 12+0.001152

L2 = 12.001152m

Expansion will be the change in length L2-L1 = 12.001152-12

= 0.001152m

The expansion cracks between the slabs should be 0.001152m wide to prevent buckling

5 0
3 years ago
Ezra (m = 20.0 kg) has a tire swing and wants to swing as high as possible. He thinks that his best option is to run as fast as
Dmitriy789 [7]

Answer:

a) v=5.6725\,m.s^{-1}

b) h= 1.6420\,m

Explanation:

Given:

  • mass of the body, M=20\,kg
  • mass of the tyre,m=10\,kg
  • length of hanging of tyre, l=3.5m
  • distance run by the body, d=10m
  • acceleration of the body, a=3.62m.s^{-2}

(a)

Using the equation of motion :

v^2=u^2+2a.d..............................(1)

where:

v=final velocity of the body

u=initial velocity of the body

here, since the body starts from rest state:

u=0m.s^{-1}

putting the values in eq. (1)

v^2=0^2+2\times 3.62 \times 10

v=8.5088\,m.s^{-1}

Now, the momentum of the body just before the jump onto the tyre will be:

p=M.v

p=20\times 8.5088

p=170.1764\,kg.m.s^{-1}

Now using the conservation on momentum, the momentum just before climbing on the tyre will be equal to the momentum just after climbing on it.

(M+m)\times v'=p

(20+10)\times v'=170.1764

v'=5.6725\,m.s^{-1}

(b)

Now, from the case of a swinging pendulum we know that the kinetic energy which is maximum at the vertical position of the pendulum gets completely converted into the potential energy at the maximum height.

So,

\frac{1}{2} (M+m).v'^2=(M+m).g.h

\frac{1}{2} (20+10)\times 5.6725^2=(20+10)\times 9.8\times h

h\approx 1.6420\,m

above the normal hanging position.

3 0
3 years ago
A medical ultrasound imaging system sends out a steady stream of very short pulses. To simplify analysis, the reflection of one
arlik [135]

Answer:

Minimum time = 1.95x10^-4 s

Number of pulses = 5128.21 pulses/s

Explanation:

We have the speed of sound waves through human tissue with a value of 1540 m/s, to calculate the time it takes for the pulse to travel a distance of 30 cm (since the pulse will first travel a distance of 15 cm and then it will return another 15 cm to be detected by the equipment), therefore, the time between the two pulses will be equal to:

tminimum = 0.30 m/1540 m/s = 1.95x10^-4 s

To calculate the number of pulses, one second must be divided over the minimum time between the two pulses, as follows:

npulses = 1 s/1.95x10^-4 s = 5128.21 pulses/s

5 0
3 years ago
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aliya0001 [1]
Animals will then have to adapt to their new environment. they might have to change their diet and get new homes.
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4 years ago
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To make the jump, Neo and Morpheus have pushed against their respective launch points with their legs applying a _____ to the la
Nimfa-mama [501]
Force is the interaction that changes the motion of an object. If we want to make a jump, our legs have to exert a force to the ground (or launch points), so that we can gain an equal and opposite force that changes our motion from being static on the ground to moving forward.
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