Answer:
13.8 N
Explanation:
Pressure on the one end of the hydraulic system = Pressure on the other end
Pressure = Force / Area where Force is in Newton, area is in m²
so Force of one end (F1) / area of that end = force of the other end (F2) / area of that end
3112 / ( 707 /10000) in m² = F2 / ( 3.14 / 10000) in m²
cross multiply
44016.97 × 0.000314 = 13.82 N
Its either releasing a stretch rubber band and a ball rolling down a hill because rubber have a potential to move when its stretch and its an eleastic potential energy also a ball rolling down a hill is a gravitational to kinetic energy because the ball started at rest which is art the top of the hill and it has a potential to fall. Once its started rolling its energy transfer into kinetic energy.
Hope this helps
Answer:
Option A
,
Explanation:
When the ball its thrown up, at half way of its flight it means half of its vertical height which is
.
potential energy = mgh
since it moved half way of height
P.E = 
This means for the body to have gained half of its P.E, it will loose half of its kinetic energy.
Final kinetic energy(
) = E/2
kinetic energy = 
let the final velocity at halfway flight be v1
= E/2
=
cross multiply we have
=
cancel m from both sides
= 
take the square root of both sides,


Thus our final velocities will be E/2 and 
Answer:
the engine cool to 40
at 14.07 minutes
Explanation:
Given information
T(5) = 70
= 100
C = 15
Newton's law of cooling :
T(t) = C + (
- C) 
where
T(t) = temperature at any given time
C = surrounding temperature
= initial temperature of heated object
k = cooling constant
to find the the time when the engine will be cooled down to 40
, we first need to find the cooling constant, k
when t = 5, T(5) = 70
so,
T(t) = C + (
- C) 
T(5) = 15 + (100 - 15) 
70 = 15 + (85) 
= (70 - 15) / 85
-5k = ln (55/85)
k = - ln (55/85) / 5
k = 0.087
thus, we have the eqaution
T(t) = 15 + (85) 
now we can determine the time when T(t) = 40
40 = 15 + (85) 
= (40-15)/85
-0.0087t = ln (25/85)
t = - ln (25/85)/0.087
t = 14.07 minutes