You use a rope 2.00 m long to swing a 10 kg weight around your head. The tension in the rope is 20 N. In half a revolution how m
1 answer:
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The force required to slow the truck was -5020 N
Explanation:
First of all, we find the acceleration of the truck, which is given by
where
v is the final velocity
u is the initial velocity
t is the time
For the truck in this problem,
v = 11.5 m/s
u = 21.9 m/s
t = 2.88 s
So the acceleration is
where the negative sign means that this is a deceleration.
Now we can find the force exerted on the truck, which is given by Newton's second law:
where
m = 1390 kg is the mass of the truck
is the acceleration
And substituting,
So the closest answer among the option is -5020 N.
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Answer:
N2- N1 = V g
Explanation:
Let's use for this exercised the equilibrium relationship
∑ F = 0
N -W = 0
N = W = mg
Let's use density redefinition
ρ = m / v
m = ρ V
N₁ = (ρ V) g
Repeat for when the liquid is submerged, in this case an upward thrust appears as a result of the water dispensed (rgow)
N₂ + B - W = 0
N₂ = W - B
B = g
= m / V
=
V
N = ρ V g - Vg
N2 = N1 + V g
N2- N1 = V g