Answer:
F = 2074.13 lb
Explanation:
Given that,
Mass of car, m = 2800 lb = 1270.059 kg
Initial speed, u = 5 mi/h = 2.2352 m/s
Final speed, v = - 1.5 mi/h = -0.67056 m/s (in opposite direction)
Time, t = 0.4 s
We need to find the magnitude of the average horizontal force (lb) exerted on the car during the impact. It can be calculated as :
or
F = -2074.13 lb
So, the required force is 2074.13 lb.
The answer is might be 352
Answer:
A. 1.6 Hz
B. 1000 m/s²
C. 50000 N
Explanation:
A. Determination of the frequency.
Period (T) = 0.625 s
Frequency (f) =?
f = 1/T
f = 1/0.625
f = 1.6 Hz
B. Determination of the acceleration.
Radius (r) = 10 m
Velocity (v) = 100 m/s
Acceleration (a) =?
a = v²/r
a = 100² / 10
a = 10000 / 10
a = 1000 m/s²
C. Determination of the net force.
Mass (m) = 50 Kg
Acceleration (a) = 1000 m/s²
Net force (F) =?
F = ma
F = 50 × 1000
F = 50000 N
I believe that your acceleration would be 4 m/s
