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2 years ago

A ball X of mals 1 kg travelling at 2 m/s has a

Physics

2 answers:

mina [271]2 years ago

7 0

Answer:

Explanation:

ikadub [295]2 years ago

5 0

Answer:

2m/s

Explanation:

If X stops Y takes momentum and it has the same velocity

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A jet leaves a runway whose bearing is N 3232degrees°E from the control tower. After flying 77 miles, the jet turns 90degrees°

OverLord2011 [107]

Answer:

$N(80.8^{\circ})E$

Explanation:

Bearing from control tower= $N(32^{\circ}+\theta})E$

But $tan \theta=\frac {opposite}{adjacent}$

$tan \theta=\frac {88}{77}$

$\theta=tan^{-1}(\frac {88}{77})=tan^{-1}(1.142857143)=48.81407483^{\circ}\approx 48.8^{\circ}$

Therefore, the bearing from control tower= $N(32^{\circ}+48.8^{\circ}})E$

Bearing= $N(80.8^{\circ})E$

The direction is North East

7 0

3 years ago

If it were possible to remove gravity and friction, think about what would happen to a football if it were tossed into the air.

elena-14-01-66 [18.8K]

Ignoring fluid resistance, football will <span>maintain a constant speed until other forces accelerate the football.</span>

6 0

3 years ago

Read 2 more answers

A net force of 125 N accelerates a 25.0 kg mass. What is the resulting acceleration?

Neko [114]

Answer: $a=5 m/s^2$

Explanation:

The acceleration of an object can be calculated by using Newton's second law:

$F=ma$

where

F is the net force applied on the object

m is the mass of the object

a is its acceleration

In this problem, we have F=125 N and m=25.0 kg, so we can rearrange the equation to calculate the acceleration:

$a=\frac{F}{m}=\frac{125 N}{25.0 kg}=5 m/s^2$

5 0

3 years ago

Read 2 more answers

?/1 Jorge traveled 5 miles north to school. He then traveled 3 miles west to the store. Then he left the store and traveled 5 mi

aleksklad [387]

Answer:

He's 3 miles west of school.

Explanation:

He went 5 miles up and 5 miles down which means that he really didn't go up or down. In between that, he went 3 miles west so if the 5 milers don't count, this puts him at 3 miles west of school.

4 0

3 years ago

Compare the maximum rate of heat transfer to the basal metabolic rate by converting a bmr of 88 kcal/hr into watts. what is the

elena-14-01-66 [18.8K]

Explanation :

It is given that,

BMR i.e basal metabolic rate is 88 kcal/hr. So, BMR in watts is converted by the following :

We know that, 1 kilocalorie = 4184 joules

So, $1\ kcal/h=\dfrac{1\times 4184\ J}{3600\ sec}$

$1\ kcal/h=1.16\ J/sec$

J/sec is nothing but watts.

So, $1\ kcal/h=1.16\ watts$

and $88\ kcal/h=88\times 1.16\ watts = 102.08\ watts$

So, it can be seen that the body can accommodate a modes amount of activity in hot weather but strenuous activity would increase the metabolic rate above the body's ability to remove heat.

8 0

3 years ago