1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vsevolod [243]
3 years ago
8

Please help me!! You don’t need a number for it just an expression

Mathematics
1 answer:
Delvig [45]3 years ago
8 0
The answer would be A/ x+y.
First you would need to place the x+y into parenthesis with the z on the outside of the parenthesis in which would be z(x+y)=A. Then you would divide both sides by x+y. This would leave you with z= A/x+y
You might be interested in
Pls help it due ASAP <br> Show workings <br> Pleaseeeeeeeeeeeee
Talja [164]
D
5 + 29 = 34/2 = 17
7 - 15 = -8/2 = -4
(17,-4)
3 0
3 years ago
Use the distributive property to multiply.<br><br> -(-16m-1)
Pepsi [2]

Answer:

16m+1

Step-by-step explanation:

Knowing about our proprieties about parentheses and negatives, let's solve this out.

<u>A negative multiplied by a negative give you a positive</u>

therefore....

-(-16m-1)= 16m+1

The -1 also receives the negative because the problem was in a parentheses :)

8 0
3 years ago
Me ajuda ai por favor tenho que entregar amanhã
elena-14-01-66 [18.8K]

a) (2a - b)² = (4a² - 4ab + b²)

b) (10m - n²)² = (100m² - 20mn² + n⁴)

c) (4x - 4²) = (16x² - 8x + 4⁴)

d){( \frac{1}{3} x - y) }^{2}  =  ({ \frac{1}{9}x }^{2}  -  \frac{2}{3} xy +  {y}^{2} )

e)

(0.25 - a) ^{2}  = (0.25^{2}  - (2)(0.25)a +  {a}^{2} ) \\  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \: \:  = ( \frac{1}{16}  -  \frac{1}{2} a +  {a}^{2} )

f)

{( \frac{2x}{3}  -  \frac{1}{2} )}^{2}  = ( \frac{4 {x}^{2} }{9}  -  \frac{2x}{3}   +  \frac{1}{4} )

6 0
3 years ago
Please Help
Jlenok [28]

Histograms are useful when we have data which can be divided into several classes or groups. The histogram shows the trend of each class and the trend among the different classes. For example when we have about 50 different values ranging from 1 to 20, it will be a better approach to draw a histogram in this case by dividing the data into small ranges e.g 1 to 4, 5 to 9 and so on and counting the frequency for each class.

Dot plot is useful when we have a small number of individual values. In this case we can visualize how many times each individual value occurred in the data. This is useful when the number of values in the data is less.

In the given scenario, we have 12 values in total ranging from 1 to 5. So making a dot plot would be the best choice. A histogram would not be useful in this case.

Therefore, the correct answer is option D. Dot plot, because a small number of scores are reported individually

7 0
3 years ago
Read 2 more answers
Find an equation for the line that passes through the points (2,-6) and (-4,-4)​
ollegr [7]

Answer:

-1/3 I think

Step-by-step explanation:

use the slope formula

4 0
3 years ago
Other questions:
  • Tennessee has a population of about 6,495,978. Its territory can be modeled as a trapezoid, as shown in the figure. Each unit on
    11·1 answer
  • Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid $15 more than
    15·1 answer
  • Find the equation of the horizontal line that contains the point left parenthesis negative 3 comma 2 right parenthesis . express
    8·1 answer
  • How do you do surface area and volume?
    5·2 answers
  • #7 You sign up for 18 weeks
    6·1 answer
  • 3, 0, -3, 0, 3, 0 what's the pattern
    9·1 answer
  • Cube root of b to the 27 power​
    15·1 answer
  • Erin and Aimee are each responsible for mowing half of their back yard. the yard is rectangular with dimensions 75 feet by 90 fe
    6·1 answer
  • Help me please and no links
    12·2 answers
  • Is the question: Do prefer doing cool math problems or reading about old boring history? fair or biased
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!