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alexira [117]
1 year ago
10

Calculate the volume of a sphere that has a radius of 4 meters

Mathematics
2 answers:
Olegator [25]1 year ago
7 0

Answer:

803.84 m³

Step-by-step explanation:

The formula to find the volume of a sphere is:

V = 4 π r³

Given that,

radius ⇒ 4m

<u>Let us find the volume now.</u>

V = 4 π r³

V = 4 π × ( 4 )³

V = 4 π × 64

V = 4 π × 64

V = 12.56 × 64

V = 803.84 m³

KIM [24]1 year ago
5 0

Answer:

268.08

Step-by-step explanation:

  • use the formula 4/3πr^3
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Solve the following differential equation: (2x+5y)dx+(5x−4y)dy=0 *Hint: they are exact<br><br> C=.
Tpy6a [65]

Answer with Step-by-step explanation:

The given differential equation is

(2x+5y)dx+(5x-4y)dy=0

Now the above differential equation can be re-written as

P(x,y)dx+Q(x,y)dy=0

Checking for exactness we should have

\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}

\frac{\partial P}{\partial y}=\frac{\partial (2x+5y)}{\partial y}=5

\frac{\partial Q}{\partial x}=\frac{\partial (5x-4y)}{\partial x}=5

As we see that the 2 values are equal thus we conclude that the given differential equation is exact

The solution of exact differential equation is given by

u(x,y)=\int P(x,y)dx+\phi(y)\\\\u(x,y)=\int (2x+5y)dx+\phi (y)\\\\u(x,y)=x^2+5xy+\phi (y)

The value of \phi (y) can be obtained by differentiating u(x,y) partially with respect to 'y' and equating the result with P(x,y)

\frac{\partial u}{\partial y}=\frac{\partial (x^2+5xy+\phi (y)))}{\partial y}=Q(x,y))\\\\5y+\phi '(y)=(5x-4y)\\\\\phi '(y)=5x-9y\\\\\int\phi '(y)\partial y=\int (5x-9y)\partial y\\\\\phi (y)=5xy-\frac{9y^2}{2}\\\\\therefore u(x,y)=x^2+10xy-\frac{9y^2}{2}+c

5 0
3 years ago
PLEASE HELP i will give you a brainly
Lady bird [3.3K]

Answer:JKL and ∠RST are complementary.

m∠JKL = 36° and m∠RST = ( x + 15)°.

Find the value of x and the measure of ∠RST .

complementary angles are two angles whose sum is 90°

36%2Bx+%2B+15=90°

51%2Bx+=90°

x+=90-51°

x+=39°

->the measure of ∠RST== ( 39 + 15)=54°

both answer and explanation

8 0
3 years ago
A parcel delivery service will deliver a package only if the length plus girth​ (distance around) does not exceed 84 inches. ​(A
Kisachek [45]

Answer:

A. 14x14x28

B. The maximum volume is 5488 cuibic inches

Step-by-step explanation:

The problem states that the box has square ends, so you can express volume with:

v=x^{2} y

Using the restriction stated in the problem to get another equation you can substitute in the one above:

4x+y=84\\\\

Substituting <em>y</em> whit this equation gives:

v=x^{2} (84-4x)\\\\v=84x^{2} -4x^{3}

Now find the limit of <em>x</em>:

\frac{84x^{2}-4x^{3}}{dx}=168x-12x^{2}\\\\x=\frac{168}{12}=14

Find the length:

y=84-4(14)=28

You can now calculate the maximum volume:

v=(14)^{2}(28)= 5488

6 0
3 years ago
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