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alexira [117]
2 years ago
10

Calculate the volume of a sphere that has a radius of 4 meters

Mathematics
2 answers:
Olegator [25]2 years ago
7 0

Answer:

803.84 m³

Step-by-step explanation:

The formula to find the volume of a sphere is:

V = 4 π r³

Given that,

radius ⇒ 4m

<u>Let us find the volume now.</u>

V = 4 π r³

V = 4 π × ( 4 )³

V = 4 π × 64

V = 4 π × 64

V = 12.56 × 64

V = 803.84 m³

KIM [24]2 years ago
5 0

Answer:

268.08

Step-by-step explanation:

  • use the formula 4/3πr^3
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emily earns $75 per day plus a commission. her commission is 15%. she sells $600 worth of furniture. how much does she earn for
iragen [17]

It would be $165. If she earns $75 a day, plus what she make from selling the furniture. That 15% of $600 is $90. Simply add $90+$75 and your answer is $165.

5 0
3 years ago
One number is 5 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 492,
Lena [83]

Answer:

The numbers are 56, 280 and 156

Step-by-step explanation:

Let

x -----> the first number

y ----> the second number

z ----> the third number

we know that

y=5x -----> equation A

z=x+100 ----> equation B

x+y+z=492 ----> equation C

Solve the system of equations by substitution

substitute equation B and equation A in equation C and solve for x

x+5x+x+100=492

7x=492-100

7x=392

x=56

<u><em>Find the value of y</em></u>

y=5x -----> y=5(56)=280

<u><em>Find the value of z</em></u>

z=x+100 ----> z=56+100=156

therefore

The numbers are 56, 280 and 156

8 0
3 years ago
Evaluate the indicated limit algebraically. Change the form of the function where necessary. Please write clearly with descripti
alukav5142 [94]

Answer:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Step-by-step explanation:

We want to evaluate the limit:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}

To do so, we can divide everything by <em>x</em>². So:

=\displaystyle \lim_{x\to \infty}\frac{3+4.5/x^2}{1-1.5/x^2}

Now, we can apply direct substitution:

\Rightarrow \displaystyle \frac{3+4.5/(\infty)^2}{1-1.5/(\infty)^2}

Any constant value over infinity tends towards 0. Therefore:

\displaystyle =\frac{3+0}{1+0}=\frac{3}{1}=3

Hence:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3<em>x</em>²<em>, </em>and in the denominator it is <em>x</em>². So:

\displaystyle \Rightarrow \lim_{x\to\infty}\frac{3x^2}{x^2}

Simplify:

\displaystyle =\lim_{x\to\infty}3=3

The limit of a constant is simply the constant.

We acquire the same answer.

6 0
3 years ago
Which situation CANNOT be represented by this equation?
fomenos
The second one, because the price of the candle is $4, meaning the equation would have to be 4x+3=19
8 0
3 years ago
Round the number to the place of the underlined digit.<br><br> 4.327 (The underlined Digit is 3)
Genrish500 [490]

Answer:4.3

You round to the tenths place

5 0
3 years ago
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