Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
Help her with the dishes
Ask her whats wrong and how you can help
Pick it up and put it in the trash
Tell him its not nice and to treat other how you want to be treated.along with telling the teacher.
28 is the correct answer.
We are asked to find for an expression that represents the perimeter of a picture frame which has a shape of a rectangle. The dimensions given are length of size x cm and a width of size 9 cm.
The formula for the Perimeter of a rectangle is given by
P=2L+2W
where L is the length and W is the width of the rectangle.
Hence,
P=2(x)+2(9)
Simplifying this values would give us a result of,
P=2x+18
Therefore, 2x+18 is the expression that represent the perimeter of the picture frame.
Step-by-step explanation:
okay so im in 8th grade and i just worked the problem out and i got , 809 ,
first you add 230 + 349 to see how much she has in her farm
she has 579, then you add 579 because she has that many , and he has 230 so you add 579 +230 and tou get 809
work:
230
+349
----------
579
+230
---------
809
hope i helped!!
