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3 years ago

10

A gym charges a one-time fee of $75 to join, plus membership dues of $25 per month. Which equation represents the total cost, C,

of belonging to the gym for m months

1 answer:

deff fn [24]3 years ago

3 0

Answer:

75+25=100

Step-by-step explanation:

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Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
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\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

7 0

2 years ago

4d = 30 the answer would be c=7.5 right if not plz correct me if im wrong

SashulF [63]

Answer:

Correct!

Step-by-step explanation:

You did it the correct mathematical way, where you divide 4 by 30. Some people get confused and multiply 30 and 4, so good job!

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2 years ago

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Aliun [14]

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3 0

2 years ago

In the figure below, PDW and WTC are right triangles. The measure of WPD is 30°, the measure of WC is 6 units, the measure of WT

aliya0001 [1]

Answer:

PD = 12 $\sqrt{3}$

Step-by-step explanation:

Using the tangent ratio in right Δ PDW and the exact value

tan30° = $\frac{1}{\sqrt{3} }$ , then

tan30° = $\frac{opposite}{adjacent}$ = $\frac{WD}{PD}$ = $\frac{12}{PD}$ = $\frac{1}{\sqrt{3} }$ ( cross- multiply )

PD = 12 $\sqrt{3}$

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2 years ago

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How can found thw length of arectngle

Minchanka [31]

If you have the area of the rectangle, then the equation would be A = W*L

Lets say the area is 15 and the width is 3. You don't know what the length is. Just divide 3 into 15 to get 5. Hope this helps!

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3 years ago