1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Digiron [165]
3 years ago
13

Which of the following apply to unsaturated hydrocarbons? Select all that apply.

Chemistry
2 answers:
Varvara68 [4.7K]3 years ago
7 0
The answer is c!!!!!!!
jek_recluse [69]3 years ago
3 0
I understand that we are able to pick "select that would apply", but based on my information, I believe that the correct answer would actually be (option c) mainly because this would relate to the definition of the word "<span>hydrocarbons".</span>
You might be interested in
Pressure gauge at the top of a vertical oil well registers 140 bars. The oil well is 6000 m deep and filled with natural gas dow
andreyandreev [35.5K]

Explanation:

(a)  The given data is as follows.

              Pressure on top (P_{o}) = 140 bar = 1.4 \times 10^{7} Pa       (as 1 bar = 10^{5})

              Temperature = 15^{o}C = (15 + 273) K = 288 K

         Density of gas = \frac{PM}{ZRT}

                \frac{dP}{dZ} = \rho \times g

               \frac{dP}{dZ} = \int \frac{PM}{ZRT}

                \int_{P_{o}}^{P_{1}} \frac{dP}{dZ} = \frac{Mg}{ZRT} \int_{0}^{4700} dZ

           ln (\frac{P_{1}}{P_{o}}) = \frac{18.9 \times 10^{-3} \times 9.81 \times 4700 m}{0.80 \times 8.314 J/mol K \times 288 K}

                              = 0.4548

                     P_{1} = P_{o} \times e^{0.4548}

                                 = 1.4 \times 10^{7} Pa \times 1.5797

                                 = 2.206 \times 10^{7} Pa

Hence, pressure at the natural gas-oil interface is 2.206 \times 10^{7} Pa.

(b)   At the bottom of the tank,

                 P_{2} = P_{1}  + \rho \times g \times h

                             = 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]

                             = 309.8 \times 10^{5} Pa

                             = 309.8 bar

Hence, at the bottom of the well at 15^{o}C pressure is 309.8 bar.

6 0
4 years ago
The following equilibrium is formed when copper and bromide ions are placed in a solution:
JulsSmile [24]

Answer:

A)

1. Reaction will shift rightwards towards the products.

2. It will turn green.

3. The solution will be cooler..

B) It will turn green.

Explanation:

Hello,

In this case, for the stated equilibrium:

heat + Cu(H_2O)_6 ^{+2} (blue) + 4Br^- \rightleftharpoons 6H_2O + CuBr_4^{-2} (green)

In such a way, by thinking out the Le Chatelier's principle, we can answer to each question:

A)

1. If potassium bromide, which adds bromide ions, is added more reactant is being added to the solution, therefore, the reaction will shift rightwards towards the products.

2. The formation of the green complex is favored, therefore, it will turn green.

3. The solution will be cooler as heat is converted into "cold" in order to reestablish equilibrium.

B) In this case, as the heat is a reactant, if more heat is added, more products will be formed, which implies that it will turn green.

Regards.

3 0
3 years ago
Which of the following is true about two neutral atoms of the element gold? (1 point) The nucleus is missing in both. Each has a
klio [65]

i have the same question idk the anwser tho

5 0
3 years ago
effect. RbClO(s) → Rb+(aq) + ClO−(aq) HClO(aq) + H2O(l) equilibrium reaction arrow H3O+(aq) + ClO−(aq) The degree of dissociatio
Lemur [1.5K]

Explanation:

Common ion effect is defined as the effect which occurs on equilibrium when a common ion (an ion which is already present in the solution) is added to a solution. This effect generally decreases the solubility of a solute.

Equilibrium reaction of strontium sulfate and sodium sulfate follows the equation:

RbClO(s)\rightarrow Rb^{+}(aq.)+ClO^{-}(aq.)

HClO(aq)+H_2O\rightleftharpoons H_3O^+(aq.)+ClO^{-}(aq.)

According to Le-Chateliers principle: If there is any change in the variables of the reaction, the equilibrium will shift in the direction in order to minimize the effect.

In the equilibrium reactions, hypochlorite ion is getting increased on the product side, so the equilibrium will shift in the direction to minimize this effect, which is in the direction of hydrogen hypochlorite.

Thus, the addition hypochlorite ions will shift the equilibrium in the left direction.

The dissociation of hydrogen hypochlorite is suppressed due to the common ion effect.

8 0
4 years ago
Can someone help?
victus00 [196]
1. <span>The answer should be combustion

2. </span><span>Water is known to successfully dissolve both acids and bases, and water is considered a universal solvent.

3. The answer should be balanced.

Hope this helps :)
</span>
7 0
4 years ago
Read 2 more answers
Other questions:
  • Which lists mixtures, in order, from the smallest particles to the largest particles?
    5·2 answers
  • A weather balloon is inflated to a volume of 2.2 x 10^3 L with 37.4 g of helium. What is the density of helium in grams per lite
    13·1 answer
  • TIMED PLS HELP ASAP AND WILL GIVE BRAINLIST
    13·1 answer
  • Strontium-90, a radioactive isotope with applications in medicine, has a half-life of approximately 30 years. Out of a 100-gram
    7·1 answer
  • PLZ HELP ME WITH MY WORK​
    8·2 answers
  • Net ionic equation of HF(aq)+RbOH(aq)=H2O(l)+RbF(aq)
    6·1 answer
  • If you have 5 unknowns and they were secondary alcohol aldehyde, carboxylic acid, amine, and alkane Put plan to identify the unk
    8·1 answer
  • Which of the following describes experiences initiated spontaneously by children as they go about their daily activities?
    10·1 answer
  • What was the name of yesterday's supermoon​
    6·1 answer
  • Over time, as their free fatty acid (FFA) content increases, edible fats and oils become rancid. To measure rancidity, the fat o
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!