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siniylev [52]
3 years ago
15

radioisotope actinium 225 has half life of 10 days, I begin with 16 kg of this isotope, how much will remain after 40 days?

Chemistry
1 answer:
Igoryamba3 years ago
3 0
N(t)=N_{0}(\frac{1}{2})^\frac{t}{\tau_{_\frac{1}{2}}}}\\\\
N_{0}=16kg\\
t=40days\\
\tau_{_\frac{1}{2}}}=10days\\\\\\
N(t)=16kg*(\frac{1}{2})^{\frac{40}{10}}=16kg*\frac{1}{16}=1kg
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Explanation:

The chemical reaction given in the question is as follows -

MnO₄⁻ (aq) + 8H⁺ (aq) + 5e⁻ → Mn²⁺ (aq) + 4H₂O (l)

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