radioisotope actinium 225 has half life of 10 days, I begin with 16 kg of this isotope, how much will remain after 40 days?

1 answer:

3 0

$N(t)=N_{0}(\frac{1}{2})^\frac{t}{\tau_{_\frac{1}{2}}}}\\\\
N_{0}=16kg\\
t=40days\\
\tau_{_\frac{1}{2}}}=10days\\\\\\
N(t)=16kg*(\frac{1}{2})^{\frac{40}{10}}=16kg*\frac{1}{16}=1kg$

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