We know that
the equation of the vertical parabola in the vertex form is
<span>y=a(x-h)²+k
</span>where
(h,k) is the vertex of the parabola
if a> 0 then
the parabola opens upwards
if a< 0
then the parabola open downwards
in this problem we have
f(x)=−5(x+7)²<span>+6
</span>a=-5
so
a< 0 -------> the parabola open downwards
the vertex is the point (-7,6) is a maximum
the answer is the option<span>
a = -5, opens down</span>
see the attached figure
Answer:
Step-by-step explanation:
Refer to the diagram shown below.
Because ΔABC is isosceles and AB = AC, therefore
m∠C = m∠B = (3x + 5)°
The sum of angles in a triangle is 180°, therefore
2(3x + 5) + 2x - 20 = 180
6x + 10 + 2x - 20 = 180
8x - 10 = 180
8x = 190
x = 23.75°
Therefore
m∠C = 3x + 5 = 3(23.75) + 5 = 76.25°
Answer: 76.25°
Answer:
not sure ia may give wrong answer