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evablogger [386]
3 years ago
8

The function C(x)=−20x+1681 represents the cost to produce x items. What is the least number of items that can be produced so th

at the average cost is no more than $21?
Mathematics
1 answer:
Reptile [31]3 years ago
8 0

Answer:

<em>The least number of items to produce is 41</em>

Step-by-step explanation:

<u>Average Cost</u>

Given C(x) as the cost function to produce x items. The average cost is:

\displaystyle \bar C(X)=\frac{C(x)}{x}

The cost function is:

C(x) = -20x+1681

And the average cost function is:

\displaystyle \bar C(X)=\frac{-20x+1681}{x}

We are required to find the least number of items that can be produced so the average cost is less or equal to $21.

We set the inequality:

\displaystyle \frac{-20x+1681}{x}\le 21

Multiplying by x:

-20x+1681 \le 21x

Note we multiplied by x and did not flip the inequality sign because its value cannot be negative.

Adding 20x:

1681 \le 21x+20x

1681 \le 41x

Swapping sides and changing the sign:

41x \ge 1681

Dividing by 41:

x\ge 41

The least number of items to produce is 41

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