A lock consists of 3 dials, where each dial has 4 letters. What is the probability of guessing the right combination in one try?

Mathematics

2 answers:

Alex17521 [72]3 years ago

6 0

1/12 because 3*4=12 and it has 4 letters

IgorC [24]3 years ago

4 0

Answer:

D.1/64

B.1 in 12

A.64%

Step-by-step explanation:

Each dial has 4 letters and only one of them is correct; the probability to choose the correct one is then 1/4. Selecting a letter in each dial is independent, then the probability of guessing the right combination in one try is 1/4 * 1/4 * 1/4 = 1/64

8% means a probability of 8/100 or an odds of 8 in 100. Dividing each term by 8 we get 8/8 = 1 in 100/8 = 12.5, which can be rounded to 1 in 12

80% means a probability of 80/100 = 0.8. Given that the 2 free-throws are independent, the probability that he makes both is 0.8*0.8 = 0.64 or 64%

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