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LUCKY_DIMON [66]
3 years ago
5

Simplify. Help me ASAP please

Mathematics
2 answers:
Doss [256]3 years ago
8 0

Answer:

option C is the correct answer my friend

melomori [17]3 years ago
3 0
I’m pretty sure it should be c :)
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Answer:

Step-by-step explanation:

%change=100(final-initial)/(initial)

%change=100(40-32)/32

%change=25%

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How many natural numbers are between 8 2 and 9 2 ?
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Here is your answer mate







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(PLEASE HELP ASAP)
UNO [17]

9514 1404 393

Answer:

  A. 3×3

  B. [0, 1, 5]

  C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.

Step-by-step explanation:

A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.

This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...

  A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)

Matrix A is 3×3.

__

B. The second row of A represents the second equation:

  0x_1+1x_2+5x_3=-1

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.

__

C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)

6 0
2 years ago
What is the fourth term in the binomial expansion (a+b)^6)
Dafna11 [192]

Answer:

20a^3b^3

Step-by-step explanation:

<u>Binomial Series</u>

(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n

<u>Factorial</u> is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example:  4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3

\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3

\implies \dfrac{6!}{3!3!}a^{3}b^3

\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3

\implies \left(\dfrac{120}{6}\right)a^{3}b^3

\implies 20a^3b^3

7 0
1 year ago
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