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BARSIC [14]
3 years ago
11

What is the solution to the following equation? 3/8 x + 6(x + 3) = -5( 1/4 x - 1) + 6x x = -13 x = 13 x = 8 x = -8

Mathematics
1 answer:
Levart [38]3 years ago
4 0

3 \div 8x + 6x + 3x =  - 5 \times 1  \div 4x -  - 5 \times 1 + 6xx =   - 13x = 13x = 8x =  - 8
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The distributive property
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3 years ago
Please solve all if you do I’ll give brainly
riadik2000 [5.3K]

Answer:

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7 0
2 years ago
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sergeinik [125]

Answer:

A. x = 58°

B. x = 10m

C. a = 44°

All approximated to nearest whole number.

Step-by-step explanation:

All triangles given are right angled triangles. Therefore, we would apply the trigonometry functions to solve for each missing side and angle.

Recall: SOHCAHTOA

a. Adjacent = 4.8cm,

Hypotenuse = 9cm

Angle to find =x°

Thus, we would apply the following formula:

Cos θ = Adjacent/Hypotenuse

Cos θ = 4.8/9 = 0.5333

θ = Cos-¹(0.5333) = 57.77

x ≈ 58° (to nearest whole number)

b. Opposite side = x

Hypothenuse = 40 m

Included angle = 14°

We would use:

Sine θ = opposite/hypothenuse

Sin (14) = x/40

Multiply both sides by 40

40*sin(14) = x

40*0.2419 = x

x = 9.676 = 10 m (to nearest whole number)

c. Opposite = 87mm

Adjacent = 91mm

θ = a°

We would use:

Tan θ = opposite/adjacent

Tan θ = 87/91

Tan θ = 0.9560

θ = tan-¹(0.9560)

θ = a = 43.71

a ≈ 44° (to nearest whole number)

7 0
3 years ago
Please answer. Confusing me. 20 points.
Sedbober [7]
The answer is either x = -1 or x = 4.
7 0
3 years ago
What is the answer to ax+z =aw-y if you are solving for a
inysia [295]
Ax + z = aw - y....subtract aw from both sides
ax - aw + z = -y....subtract z from both sides
ax - aw = -y - z....factor out a on the left side
a(x - w) = -y - z...divide both sides by (x-w)
a = (-y - z) / (x - w)
7 0
3 years ago
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