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3 years ago

Every day the teacher has her class of ten students line up for lunch. how many different ways can the students line up?

Mathematics

1 answer:

vlada-n [284]3 years ago

6 0

That's a question for arrangement, so we have:
$A^{10}_{10}=10*9*8*7*6*5*4*3*2*1=5.4*10^{11}$

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Round 3.962 to the nearest tenths

gayaneshka [121]

It would be 4.0

please can i have a brailiest

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3 years ago

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Solve the system of equations using elimination: -8x-4y=4 and -5x-y=-11.

ziro4ka [17]

The solutions to the given system of equations are x = 4 and y = -9

<h3>Simultaneous linear equations</h3>

From the question, we are to determine the solutions to the given system of equations

The given system of equations are

-8x-4y=4 --------- (1)

-5x-y=-11 --------- (2)

Multiply equation (2) by 4

4 ×[-5x-y=-11 ]

-20x -4y = -44 -------- (3)

Now, subtract equation (3) from equation (1)

-8x -4y = 4 --------- (1)

-(-20x -4y = -44) -------- (3)

12x = 48

x = 48/12

x = 4

Substitute the value of x into equation (2)

-5x -y = -11

-5(4) -y = -11

-20 -y = -11

-y = -11 + 20

-y = 9

∴ y = -9

Hence, the solutions to the given system of equations are x = 4 and y = -9

Learn more on Simultaneous linear equations here: brainly.com/question/26310043

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6 0

1 year ago

Based on historical data, your manager believes that 41% of the company's orders come from first-time customers. A random sample

TEA [102]

Answer:

The probability that the sample proportion is between 0.35 and 0.5 is 0.7895

Step-by-step explanation:

To calculate the probability that the sample proportion is between 0.35 and 0.5 we need to know the z-scores of the sample proportions 0.35 and 0.5.

z-score of the sample proportion is calculated as

z= $\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of first time customers
p is the proportion of first time customers based on historical data

N is the sample size

For the sample proportion 0.35:

z(0.35)= $\frac{0,35-0.41}{\sqrt{\frac{0.41*0.59}{72} } }$ ≈ -1.035

For the sample proportion 0.5:

z(0.5)= $\frac{0,5-0.41}{\sqrt{\frac{0.41*0.59}{72} } }$ ≈ 1.553

The probabilities for z of being smaller than these z-scores are:

P(z<z(0.35))= 0.1503

P(z<z(0.5))= 0.9398

Then the probability that the sample proportion is between 0.35 and 0.5 is

P(z(0.35)<z<z(0.5))= 0.9398 - 0.1503 =0.7895

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3 years ago

Margo won 24 out of her last 36 tennis matches.At this rate,predict how many matches she would win out of her next 27 matches ?

adell [148]

27 out of 39 win i guess If u think this is right ok

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3 years ago

The science class is taking a trip to the science center. there are 20 students and an unknown number of adult chaperones going.

Alekssandra [29.7K]

The greatest number of adults who can chaperone
35-20 = 15

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3 years ago

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