Plan, design, and implement solar energy projects
Explanation:
there are no limits of the number of junction boxes in any particular circuit.
One
When you convert a whole number into a fraction, you put the whole number as the numerator and the denominator as 1.
Such as 12=12/1 or 5=5/1
Answer:
For the Top Side
- Strain ε = 0.00021739
- Elongation is 0.00260868 cm
For The Right side
- Strain ε = 0.00021739
-Elongation is 0.00347826 cm
Explanation:
Given the data in the question;
Length of the squared titanium plate = 12 cm by 12 cm = 0.12 m by 0.12 m
Thickness = 5 mm = 0.005 m
Force to the Top F
= 15 kN = 15000 Newton
Force to the right F
= 20 kN = 20000 Newton
elastic modulus, E = 115 GPa = 115 × 10⁹ pascal
Now, For the Top Side;
- Strain = σ/E = F
/ AE
we substitute
= 15000 / ( 0.12 × 0.005 × (115 × 10⁹) )
= 15000 / 69000000
Strain ε = 0.00021739
- Elongation
Δl = ε × l
we substitute
Δl = 0.00021739 × 12 cm
Δl = 0.00260868 cm
Hence, Elongation is 0.00260868 cm
For The Right side
- Strain = σ/E = F
/ AE
we substitute
Strain = 20000 / ( 0.12 × 0.005 × (115 × 10⁹) )
= 20000 / 69000000
Strain ε = 0.000289855
- Elongation
Δl = ε × l
we substitute
Δl = 0.000289855× 12 cm
Δl = 0.00347826 cm
Hence, Elongation is 0.00347826 cm
Answer:
The average force F exherted by the nail over the hammer is 178.4 lbf.
Explanation:
The force F exherted by the nail over the hammer is defined as:
F = |I|/Δt
Where I and Δt are the magnitude of the impact and the period of time respectively. We know that the impact can be calculated as the difference in momentum:
I = ΔP = Pf - Pi
Where Pf and Pi are the momentum after and before the impact. Recalling for the definition for momentum:
P = m.v
Where m and v are the mass and the velocity of the body respectively. Notice that final hummer's momentum is zero due to the hammers de-acelerate to zero velocity. Then the momentum variation will be expressed as:
ΔP = - Pi = -m.vi
The initial velocity is given as 50 mph and we will expressed in ft/s:
vi = 50 mph * 1.47 ft/s/mph = 73.3 ft/s
By multiplyng by the mass of 1.8 lbs, we obtain the impulse I:
|I|= |ΔP|= |-m.vi| = 1.8 lb * 73.3 ft/s = 132 lb.ft/s
Dividing the impulse by a duration of 0.023 seconds, we finally find the force F:
F = 132 lb.ft/s / 0.023 s = 5740 lb.ft/s^2
Expressing in lbf:
F = 5740 lb.ft/s^2 * 0.031 lbf/lb.ft/s^2 = 178.4 lbf