Answer:
Everything I got what you need
The correct answers are B & C; Chatter Groups and Similar opportunities.
Further Explanation:
Sales representatives can use chatter groups and other similar opportunities to their advantage. This can help them to understand and manage their products that are in direct competition with competitors.
A chatter group can be used to share ideas both privately and publicly. These groups can have more than 30,000 people or just 3 people, it depends on how many are interested in the topic or product. The groups can be made unlisted and by invite only and then you can see with whom you are talking to. Nonmembers can view anything written in the public and archived groups. This is a great way to see how your peers are doing with their product.
Learn more about chatter groups at brainly.com/question/4489111
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Answer:
The answer is "Both Technician A and Technician B".
Explanation:
The cylinder Testing is intended to assess locomotive inconsistency in CNS rodents, for example, whenever the animal moves within a transparent plastic tube, its preliminary activity is registered as it rises against the stadium wall.
In the given question both technicians are correct because both are reliable ways to check cylinders and the influence of the belief if every pathway has many more advantages than each other.
Answer:
work=281.4KJ/kg
Power=4Kw
Explanation:
Hi!
To solve follow the steps below!
1. Find the density of the air at the entrance using the equation for ideal gases
where
P=pressure=120kPa
T=20C=293k
R= 0.287 kJ/(kg*K)=
gas constant ideal for air
2.find the mass flow by finding the product between the flow rate and the density
m=(density)(flow rate)
flow rate=10L/s=0.01m^3/s
m=(1.43kg/m^3)(0.01m^3/s)=0.0143kg/s
3. Please use the equation the first law of thermodynamics that states that the energy that enters is the same as the one that must come out, we infer the following equation, note = remember that power is the product of work and mass flow
Work
w=Cp(T1-T2)
Where
Cp= specific heat for air=1.005KJ/kgK
w=work
T1=inlet temperature=20C
T2=outlet temperature=300C
w=1.005(300-20)=281.4KJ/kg
Power
W=mw
W=(0.0143)(281.4KJ/kg)=4Kw
