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2 years ago

A technician needs to check the heating operation of a heat pump that has no gauge access ports. The technician should start by:

Engineering

1 answer:

OverLord2011 [107]2 years ago

7 0

The technician should start by checking the temperature rise across the indoor coil.

<h3>Who is a technician?</h3>

This is a person who has skill in a particular area of job. A technician is responsible for repairs and also ensure different equipment and systems are working perfectly.

Hence, the technician should start by checking the temperature rise across the indoor coil.

Learn more about technician here : brainly.com/question/13315405

#SPJ1

You might be interested in

Convert 850 nm wavelength into frequency, eV, wavenumber, joules and ergs.

BabaBlast [244]

Answer:

Frequency = 3.5294×10¹⁴ s⁻¹

Wavenumber = 1.1765×10⁶ m⁻¹

Energy = 2.3365x 10⁻¹⁹ J , 1.4579 eV , 2.3365x 10⁻¹² erg

Explanation:

Given the wavelength = 850 nm

1 nm = 10⁻⁹ m

So, wavelength is 850×10⁻⁹ m

The relation between frequency and wavelength is shown below as:

c = frequency × Wavelength

Where, c is the speed of light having value = 3×10⁸ m/s

So, Frequency is:

Frequency = c / Wavelength

$Frequency=\frac {3\times 10^8\ m/s}{850\times 10^{-9}\ m}$

Frequency = 3.5294×10¹⁴ s⁻¹

Wavenumber is the reciprocal of wavelength.

So,

Wavenumber = 1 / Wavelength = 1 / 850×10⁻⁹ m

Wavenumber = 1.1765×10⁶ m⁻¹

Also,

$Energy=h\times frequency$

where, h is Plank's constant having value as 6.62x 10⁻³⁴ J.s

So,

Energy = 6.62x 10⁻³⁴ J.s × 3.5294×10¹⁴ s⁻¹

Energy = 2.3365x 10⁻¹⁹ J

Also,

1 J = 6.24×10¹⁸ eV

So,

Energy = 2.3365x 10⁻¹⁹ × 6.24×10¹⁸ eV

Energy = 1.4579 eV

Also,

1 J = 10⁷ erg

So,

Energy = 2.3365x 10⁻¹⁹ × 10⁷ erg

Energy = 2.3365x 10⁻¹² erg

8 0

3 years ago

Assuming Stokes behavior, calculate the terminal settling velocity in standard air () for the following particles: (a) diameter

inna [77]

Answer:

Detailed solution is given below :

4 0

3 years ago

When a circuit has a supermesh, you write two equations: the supermesh constraint equation and the supermesh KVL equation. You h

givi [52]

Explanation:

Note: Refer the diagram attached

Apply KVL around $i_{z}$ loop

$\begin{aligned}&5 k \left(i_{z}-i_{y}\right)+2 v_{\Delta}=0\\&5000\left(i_{z}-i_{y}\right)+2 v_{\Delta}=0 \quad \ldots \ldots(1)\end{aligned}$

$From the circuit, $v_{\Delta}$ can be expressed using ohm's law as,\\$v_{\Delta}=(1 k ) i_{y}$$v_{\Delta}=1000 i_{y}$$

3 0

3 years ago

A 1 250 kg car moving at a velocity of 30 km/hr along EDSA is accelerated by a force of 1 700 N. What will be its velocity after

Talja [164]

<h3><u>The velocity of the car after 10 s is 78.95 km/hr</u></h3>

Explanation:

<h2>Given:</h2>

m = 1,250 kg

$v_i$ = 30 km/hr

F = 1,700 N

t = 10 s

<h2>Required:</h2>

Final velocity

<h2>Equation:</h2><h3>Force</h3>

F = ma

where: F - force

m - mass

a - acceleration

<h3>Acceleration</h3>

a = $\frac{v_f \:-\:v_i}{t}$

where: a - acceleration

$v_i$ - initial velocity

$v_f$ - final velocity

t - time elapsed

<h2>Solution:</h2><h3>Solve for acceleration using the formula for force</h3>

F = ma

Substitute the value of F and m

(1700 N) = (1250 kg)(a)

a = $\frac{1700\:N}{1250\:N}$

a = 1.36 m/s²

<h3>Solve for final velocity using the formula for acceleration</h3>

Convert 30 km/hr to m/s

= $\frac{30\:km}{hr}\:×\:\frac{1000\:m}{1\:m}\:×\:\frac{1\:hr}{3600\:s}$

= $8.33 m/s$

Substitute the value of a, $v_i$ and t

a = $\frac{v_f \:-\:v_i}{t}$

$1.36\: m/s² \:= \:\frac{v_f \:-\:8.33\:m/s}{10\:s}$

$(10 \:s)1.36\: m/s² \:= \:v_f \:-\:8.33\:m/s$

$v_f\: =\: (10 \:s)1.36 \:m/s²\: + \:8.33\:m/s$

$v_f \: =\: 13.6 \:m/s \:+\: 8.33\:m/s$

$v_f\: =\: 21.93\: m/s$

Convert to km/hr

= $\frac{21.93\:m}{s}\:×\:\frac{1\:km}{1000\:m}\:×\:\frac{3600\:s}{1/:hr}$

= $78.95\: km/hr$

<h2>Final answer</h2><h3><u>The velocity of the car after 10 s is 78.95 km/hr</u></h3>

6 0

3 years ago

Given the front and right views, create an AutoCAD isometric of the object. Save the drawing as lab5c.dwg. Grid size is 10mm. Yo

ki77a [65]

Given the front and right views, create an AutoCAD isometric of the object. Save the drawing as lab5c.dwg. Grid size is 10mm. You may approximate the location of the hidden line as long as it is consistent with the other view is given below

Explanation:

1.Use CTRL-C to copy the lines to the Windows clipboard. Go to the 2D drawing and give the PASTESPEC (Paste Special) command. This will paste an image of the selected geometry into the other drawing. SInce it is an image and not AutoCAD entities the image quality will be limited.

2.Isometric drawing in AutoCAD 2014 and older versions:

At first, you need to change your snap settings to isometric. Type DS on the command line and press enter. Drafting settings window will pop up from this window select snap and grid tab and make sure Isometric snap radio button is checked.

3.To Display a Preset 3D View

Click View tab Views panel View Manager. Find. The View tab is not displayed by default, so an alternative method is to enter VIEW at the Command prompt. You can also employ the ViewCube in the top-right corner of the drawing area.

Select a preset view (Top, Bottom, Left, and so on).

4.If you aren't in model space, double-click inside the viewport to enter model space.

Go to Home tab > Modify panel (expanded)> Change Space to start the CHSPACE command.

At the prompt, select one or more objects to move.

Press Enter to end selection and the command. AutoCAD moves the selected objects to the other space.

4 0

2 years ago