Answer: downward velocity = 6.9×10^-4 cm/s
Explanation: Given that the
Diameter of the smoke = 0.05 mm = 0.05/1000 m = 5 × 10^-5 m
Where radius r = 2.5 × 10^-5 m
Density = 1200 kg/m^3
Area of a sphere = 4πr^2
A = 4 × π× (2.5 × 10^-5)^2
A = 7.8 × 10^-9 m^2
Volume V = 4/3πr^3
V = 4/3 × π × (2.5 × 10^-5)^3
V = 6.5 × 10^-14 m^3
Since density = mass/ volume
Make mass the subject of formula
Mass = density × volume
Mass = 1200 × 6.5 × 10^-14
Mass M = 7.9 × 10^-11 kg
Using the formula
V = sqrt( 2Mg/ pCA)
Where
g = 9.81 m/s^2
M = mass = 7.9 × 10^-11 kg
p = density = 1200 kg/m3
C = drag coefficient = 24
A = area = 7.8 × 10^-9m^2
V = terminal velocity
Substitute all the parameters into the formula
V = sqrt[( 2 × 7.9×10^-11 × 9.8)/(1200 × 24 × 7.8×10^-9)]
V = sqrt[ 1.54 × 10^-9/2.25×10-4]
V = 6.9×10^-6 m/s
V = 6.9 × 10^-4 cm/s
Answer:
does the question entail anything else?
Explanation:
Answer:
A to C = 6.4 km
Explanation:
A to B = 4 km
B to C = 5 km
A to C = using pythagorean theorem
a² + b² = c²
a = A to B = 4
b = B to C = 5
c = A to C
c² = 4² + 5²
c = 6.4 km (A to C)
The correct answer is "immediately flood the area with water and clean the wound."
Further Explanation:
If someone is exposed to a potentially infectious material with a sharps item such a needle, they need to wash the area with clean water immediately. It must be a steady flow of water to get out any potential infectious material.
After flushing the injury with water, you will then wash the area or exposed skin with soap, if at all possible use a disinfectant on the area.
The person who was injured should seek medical assistance for tests to be sure that they have not been affected.
Learn more about infectious material at brainly.com/question/10928952
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Answer:
V = 0.00459 ft/s
Explanation:
Since the Piston is moving downwards with a constant velocity V, from the first Newton’s law we know that all vertical forces, must have zero resultant (their sum over vertical axis must equal to zero). Therefore, force that pulls the piston down, is equalized by force of viscous friction Fd= Fvf = 0.5lb (lb here is the pound-force unit). We will relate F ѵ f with τ and from that derive the equation for V.
Fѵf = τ . A
Where τ = µ. du/dy = µ . V/b , and A = π . D . l from this Follows:
Fѵf= (V. A .µ )/b V= ( Fѵf .b )/(A.µ)
Placing all the known values in the equation ( remember to transform inches to feet, by multiplying inches values with the factor 1/12), we obtain :
ft2
V = ((0.5lb) . (0.002/12 ft))/(π . (5.48/12 ft) . (9.50/12 ft) . (0.016 lb.s/(ft^2 )))
V = 0.00459 ft/s
