Answer:
30.1 g NaCl
Explanation:
Your first conversion is converting grams NaOH to moles of NaOH using its molar mass (39.997 g/mol). Then, use the mole ratio of 1 mol NaCl for every 1 mol NaOH to get to moles of NaCl. Then finally multiply by the molar mass of NaCl (58.44 g/mol) to get grams of NaCl.
20.6 g NaOH • (1 mol NaOH / 39.997 g NaOH) • (1 mol NaCl / 1 mol NaOH) • (58.44 g NaCl / 1 mol NaCl) = 30.1 g NaCl
Answer:
the answer is True i just took the test
Explanation:
Answer : The final temperature is, 
Explanation :
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of water at 
= 150 g
= mass of water at 
= 100 g
= final temperature = ?
= temperature of lead = 
= temperature of water = 
= same (for water)
Now put all the given values in equation (1), we get
![150\times (T_{final}-363)=-[100\times (T_{final}-303)]](https://tex.z-dn.net/?f=150%5Ctimes%20%28T_%7Bfinal%7D-363%29%3D-%5B100%5Ctimes%20%28T_%7Bfinal%7D-303%29%5D)
Therefore, the final temperature is,
