Answer: The molar enthalpy change is 73.04 kJ/mol
Explanation:
moles of HCl=
As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.
volume of water = 100.0 ml + 50.0 ml = 150.0 ml
density of water = 1.0 g/ml
mass of water =
q = heat released
m = mass = 150.0 g
c = specific heat =
= change in temperature =
Thus 0.0415 mol of HCl produces heat = 3031.3 J
1 mol of HCL produces heat =
Thus molar enthalpy change is 73.04 kJ/mol
Answer:
87.15%
Explanation:
To find percent yield, we can use this simple equation
Where "Actual" is the amount in grams actually collected from the reaction, and "Theoretical" is, well, the theoretical amount that should have been produced.
They give us these values, so to find the percent yield, just plug the numbers in.
So, the percent yield is 87.15%
An easy trick to remember how to do this is just to divide the smaller number by the bigger number and move the decimal back two places. If you have a percent yield greater than 100%, something is wrong in the reaction.